|2 1 D = 3 4 |3 3 -1 3

Q: (In(r))² 9. dr

A:

Q: 3

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Q: (0-4)de (0+5) 2.

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Q: Between z= -2.42 and z=-1.77

A: We have to find area Between z= -2.42 and z=-1.77

Q: r+0.6>2

A: Solve the equation r+0.6>2

Q: -5   | -2] [1   −8  | −3]−−−−−4R2+R1 →   [  ___ ___ ___  ___  ____  ___ ]?

A: Given query is to perform 4 R2 + R1

Q: c 2 0 0 4 0 1 0 40

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Q: -4(p+2)+8=2(p-1)-7p+15

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Q: 11. (D² – 2D + 5)y = 0 12. (D² + 9)y = 0

A:

Q: a.n=50, x= 21 b.n= 150, x 112 C.n=90, x= 15 d. n=90, x=5.17

A: We have given that, Population standard deviation (σ) = 30 and following sample mean and sample size…

Q: 3) PR = 2n+ 9 7n-18 R 4) n =

A:

Q: 3. (Va² +1)* dz. Evaluate

A: Write radical in the form of fractions.

Q: 8) y=-1 +2cos 0 3 37 37C 2 2.

A: Given query is to graph the function.

Q: 2х - 10, X-3 А. 3 В. 9 С. 15 D. 30

A:

Q: 2 (d) ³² (3 [² (3 − z)(3z + 1) dz.

A:

Q: (- 1)"x" Σ 6" (n² + 9) n=1 8.

A: Given

Q: 2(3+d-1)

A: Solve the given expression  given expression is 2(3+d-1)

Q: (q/q-3) + 1 = (2/2q+1)

A: To solve for q, firstly, we take l.c.m on left hand side of equation.

Q: 24. х— бху + 9у? - о x - y = 2 блу + 9у? 9y = 0

A: From x-y=2 we get x=y+2 We substitute it in the first equation and solve for y

Q: Simplify. 3+ 0! 2!:1! O 7/2 3/2 O3

A: Here we have to find the value of the above expression  We know 0! = 1 and 1!= 1  so using the above…

Q: Зт? + 2m — 8-0 Зт? + бт —4т - 8-0 Зт (т + 2) — 4 (т + 2)30 (т + 2) (Зт — 4)30 – 4)=0 т3-2, —

A:

Q: Simplify the expression

A: Given: 4x2+912(2) - 2x+3124x2+9-128x4x2+9122  To simplify: The given expression.

Q: y(s) 2 u(s) s' 2 + 2s +3

A: The state representation can be calculated as, This can be rewritten as, Taking inverse laplace…

Q: (2) (D – 25)²(D² – 4D + 13)³y = 0

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Q: IF 2メ+3 Find d. 2 915 C 13 d. I5 xホ

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Q: {- 2x - 3y = 7 4х + бу 3 -14 29 9, 3 7 (х, у) -D 3

A:

Q: (-0.3s – 2) + (5 –3.4s) + (5r + 2)

A: Hello. Since your question has multiple parts, we will solve first question for you. If you want…

Q: -1 r + 3 1 x + 3 5 * + 3

A:

Q: 4y2 У(у + 2)(у — 3) "У 7у — 12 dy '2

A:

Q: -8 -6 АУ 6 41 d N -41 2 4 X

A: Solution

Q: 2 + 5r +4 h(r) = 3r + 5 3r + 10r + 13 O A. h'(r) =- (3r + 5)2

A: The derivative is computed using quotient rule.

Q: -5.2 + у 3 7.5 A y = у3 - 12.7 В y = - 2.3 C У- 2.3 D y = 12.7

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Q: 15. 0 = 19. r = 4seco 4 풍 풍 k|2 2 3m 3 +0 6 6

A:

Q: 3 V= ㅠ (x4 – 18x? + 81) dæ 3 18x? = T + 81x n 5 3 [(-0)-(뿌 ) -0) + 18.3 3

A:

Q: - 11 5 4 8 9. 9 3

A: Given data is appropriate for measures of central tendency.

Q: (교2 + 3)2r+1 (r – 1)3

A:

Q: 24) с 3x-1 10 5x+3 AА) 2 C) 3 B) 11 D) –12

A: The points A, B and C are collinear i. e they lie on the same line.  The total length of the line…

Q: 5. Se7*+2 dx

A: Using Substitution method of integration

Q: 1 for R (from electronics) R3 + + R R1 R2 II

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Q: F(2) = ? (1–2z)²

A:

Q: 3. Find A-1. 1 A = 3 4 0 0 1 3 32 2 2 3

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Q: -1 7. S. ze³z² −1 dz Sydy .2 8.

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Q: 6. x +1 x-2 A) 0 C) 5 В) 6 D) 8

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Q: 2n aO п .d O 2

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Q: A. y =(x – 7)2 – 6 B. y =(x + 7)² +6 C. y =(x + 7)2 – 6 D. y =(x - 7)2 + 6 5.

A: Note: As per bartleby instruction when more then one question is given only one has to be answered.…

Q: P (Z > 1.28)=?

A: Z is a random variable that follows standard normal distribution with mean 0 and variance 1.

Q: x 6 4 x+y 3. -1 2w 3 ven M+27

A:

Q: -3 7/20 greater then -3.37

A: Introduction :

Q: 1. ај3D2 d = 3 T7 =? 2. ај3 —4 d = -2 T12 =? 3. ај %3D? d = 4 Тзо 3 122

A: Formula for nth term is as below :

Q: -2 0 3 D= 5 -1 7 E = 5

A: