Order the functions by growth rate. a(x) = 1000-7890 c(x) = 9x b(x) = 20x! d(x) = x²
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- Need Help with Octave: function [w, t, flag] = margin_pcpt(X, y, max_iter, max_margin)[m, n] = size(X);flag = 0;w = zeros(n, 1);t = 1;while (t < max_iter) && (flag == 0)% Your tasks: % 1. searches for violation point p such that % (a) the label disagrees with p*w; OR % (b) the distance between p and seperation line is too close, i.e. % p*(w./norm(w, 2)) <= max_margin % 2. update the seperation plane vector w % 3. if there is no more violation point, set flag = 1. t = t + 1;end% as a good habit: normalise the seperation vector by it's normw = w./norm(w, 2);endWireless sensor networks are a special kind of network that facilitates communication. Sensor nodes in WSNs relay information to and from a central base station. The computing resources and storage space of a sensor node are limited. Take, for example, an algorithm that can be solved by solving subproblems. Is it preferable to use dynamic programming or divide and conquer to solve these subproblems independently at various sensor nodes? Try to keep your writing short and sweet.You are the sysadmin for a big tech company, and you have to estimate the amount of servers you need to handle some long-running jobs. One server can handle only one job at once. One job can only be executed by one server at once. Once a server has finished executing its current job, it can be reassigned to a new job. Given an array of time intervals intervals where intervals[i] = [starti, endi], representing the start and end time for a particular job that needs to be executed, return the minimum number of servers required to run all jobs. Constraints: 1 <= intervals.length <= 104 0 <= starti < endi <= 106 Function definition for Java: public int minMeetingRooms(int[][] intervals) { // Your code here } Function definition for Python: def minMeetingRooms(self, intervals: List[List[int]]) -> int: #Your code here Announced Test Cases: Input: intervals = [[0,30],[5,10],[15,20]] Output: 2Explanation: We need one server for the job that starts at 0. For the job…
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