P Value please? A recent study found that 61 children who watched a commercial for potato chips featuring a celebrity endorser ate a mean of 36 grams of potato chips as compared to a mean of 27 grams for 51 children who watched a commercial for an alternative food snack. Suppose that the sample standard deviation for the children who watched the celebrity-endorsed commercial was 21.3 grams and the sample standard deviation for the children who watched the alternative food snack commercial was 12.7 grams. Complete parts (a) through (d) below. a. Assuming that the population variances are equal and α=0.05, is there evidence that the mean amount of potato chips eaten was significantly higher for the children who watched the celebrity-endorsed commercial? Let population 1 be the weights of potato chips eaten by children who watched the celebrity-endorsed commercial and let population 2 be the weights of potato chips eaten by children who watched the alternative food snack commercial. What are the correct null and alternative hypotheses? A. H0: μ1−μ2≥0 H1: μ1−μ2<0 B. H0: μ1−μ2≠0 H1: μ1−μ2=0 C. H0: μ1−μ2=0 H1: μ1−μ2≠0 D. H0: μ1−μ2≤0 H1: μ1−μ2>0 Your answer is correct. What is the test statistic? tSTAT=2.652.65 (Round to two decimal places as needed.) What is the corresponding p-value? p-value=enter your response here (Round to three decimal places as needed.)
P Value please? A recent study found that 61 children who watched a commercial for potato chips featuring a celebrity endorser ate a mean of 36 grams of potato chips as compared to a mean of 27 grams for 51 children who watched a commercial for an alternative food snack. Suppose that the sample standard deviation for the children who watched the celebrity-endorsed commercial was 21.3 grams and the sample standard deviation for the children who watched the alternative food snack commercial was 12.7 grams. Complete parts (a) through (d) below. a. Assuming that the population variances are equal and α=0.05, is there evidence that the mean amount of potato chips eaten was significantly higher for the children who watched the celebrity-endorsed commercial? Let population 1 be the weights of potato chips eaten by children who watched the celebrity-endorsed commercial and let population 2 be the weights of potato chips eaten by children who watched the alternative food snack commercial. What are the correct null and alternative hypotheses? A. H0: μ1−μ2≥0 H1: μ1−μ2<0 B. H0: μ1−μ2≠0 H1: μ1−μ2=0 C. H0: μ1−μ2=0 H1: μ1−μ2≠0 D. H0: μ1−μ2≤0 H1: μ1−μ2>0 Your answer is correct. What is the test statistic? tSTAT=2.652.65 (Round to two decimal places as needed.) What is the corresponding p-value? p-value=enter your response here (Round to three decimal places as needed.)
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 26PFA
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P Value please?
A recent study found that
61
children who watched a commercial for potato chips featuring a celebrity endorser ate a mean of
36
grams of potato chips as compared to a mean of
27
grams for
51
children who watched a commercial for an alternative food snack. Suppose that the sample standard deviation for the children who watched the celebrity-endorsed commercial was
21.3
grams and the sample standard deviation for the children who watched the alternative food snack commercial was
12.7
grams. Complete parts (a) through (d) below.a. Assuming that the population variances are equal and
α=0.05,
is there evidence that the mean amount of potato chips eaten was significantly higher for the children who watched the celebrity-endorsed commercial?Let population 1 be the weights of potato chips eaten by children who watched the celebrity-endorsed commercial and let population 2 be the weights of potato chips eaten by children who watched the alternative food snack commercial. What are the correct null and alternative hypotheses?
H0:
μ1−μ2≥0
H1:
μ1−μ2<0
H0:
μ1−μ2≠0
H1:
μ1−μ2=0
H0:
μ1−μ2=0
H1:
μ1−μ2≠0
H0:
μ1−μ2≤0
H1:
μ1−μ2>0
What is the test statistic?
tSTAT=2.652.65
(Round to two decimal places as needed.)What is the corresponding p-value?
p-value=enter your response here
(Round to three decimal places as needed.)Expert Solution
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