p (x ) = x ³ – 2 -5 To evaluate p at x=5, use .a polyvalm(p,X) .b polyval(p,5) .C poly(p,5) .d All previous options
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A:
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A:
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- Algorithm Bellman_Ford1: procedure Bellman_Ford(G,s)2: for all {v} ∈ V do initialize3: d[v]←∞4: p[v] ← Ø5: end for6: d[s] ← 0 s has 0 cost7: for k = 1 to n − 1 do8: for all (u, v) ∈ E do relaxation9: if d[v] > d[u] + w[u, v] then10: d[v] = d[u] + w[u, v]11: p[v] ← u12: end if13: end for14: end for15: for all (u, v) ∈ E do16: if d[v] > d[u] + W[u, v] then17: return Ø a negative cycle detected18: end if19: end for20: return d, P21: end procedure Make Python Implementation of given algorithmSuppose we use the following KB (where x,y,z are variables and r1, r2, r3, goal are constants) to determine whether a particular robot can score a) Open(x) ∧ HasBall(x) -> CanScore(x) b) Open(x) ∧ CanAssist(y,x) ∧ HasBall(y) -> CanScore(x) c) PathClear(x,y) -> CanAssist(x,y) d) PathClear(x,z) ∧ CanAssist(z,y) -> CanAssist(x,y) e) PathClear(x,goal) -> Open(x) f) PathClear(y,x) -> PathClear(x,y) g) HasBall(r3) h) PathClear(r1, goal) i) PathClear(r2, r1) j) PathClear(r3, r2) k) PathClear(r3, goal) Intuitively, CanScore(x) means x can score on goal. CanAssist(x,y) means there exists some series of passes that can get the ball from x to y. Open(x) means x can shoot on goal directly. And PathClear(x,y) means the path between x and y is clear. Provide a SLD-derivation for the query CanScore(x) in which the answer provided is r1. Provide a SLD-derivation for the query CanScore(x) in which the answer provided is r3. How many "distinct" derivations (i.e., involving different…Subject : calculas Show that: ¬q 1) p→¬q 2) (p∧r)∨s 3) s→(t∨u) 4) ¬t∧¬u where ¬ is denied.
- Choose the mathematical statement that best describes this statement. 14. "JR, EJ and KL come to the party if and only if CK doesn't come, but, if neither JR nor EJ come, then CK comes only if KL comes." *(~P v ~Q) ^ (S -> R)(~P v ~Q) -> (S -> R)(~P v ~Q) -> (S v R)For P= 0 and compute the value of K under the condition. if (P <= 1) K = P + 5else if (P > 1 && P <= 5) K = P + 3else if (P > 8) K= P - 1else K = PLet R=ABCDEGHK and F= {ABK→C, A→DG, B→K, K→ADH, H→GE} . Is it in BCNF? Prove your answer.
- Suppose we use the following KB (where x, y, z are variables and r1, r2, r3, goal are constants) to determine whether a particular robot can score. (a) Open(x) ∧ HasBall(x) → CanScore(x)(b) Open(x) ∧ CanAssist(y, x) ∧ HasBall(y) → CanScore(x) (c) PathClear(x,y) → CanAsist(x,y)(d) PathClear(x,z) ∧ CanAssist(z,y) → CanAssist(x,y) (e) PathClear(x,goal) → Open(x)(f) PathClear(y,x) → PathClear(x,y) (g) HasBall(r3)(h) PathClear(r1,goal) (i) PathClear(r2,r1) (j) PathClear(r3,r2) (k) PathClear(r3,goal)Suppose we use the following KB (where x, y, z are variables and r1, r2, r3, goal are constants) to determine whether a particular robot can score. (a) Open(x) ∧ HasBall(x) → CanScore(x)(b) Open(x) ∧ CanAssist(y, x) ∧ HasBall(y) → CanScore(x) (c) PathClear(x,y) → CanAsist(x,y)(d) PathClear(x,z) ∧ CanAssist(z,y) → CanAssist(x,y) (e) PathClear(x,goal) → Open(x)(f) PathClear(y,x) → PathClear(x,y) (g) HasBall(r3)(h) PathClear(r1,goal) (i) PathClear(r2,r1) (j) PathClear(r3,r2) (k) PathClear(r3,goal) Intuitively, CanScore(x) means x can score on goal. CanAssist(x, y) means there exists some series of passes that can get the ball from x to y. Open(x) means x can shoot on goal directly. And P athClear(x, y) means the path between x and y is clear. Provide a SLD-derivation for the query CanScore(x) in which the answer provided is r1. Provide a SLD-derivation for the query CanScore(x) in which the answer provided is r3. How many “distinct” derivations (i.e., involving different…the logit function(given as l(x)) is the log of odds function. what could be the range of logit function in the domain x=[0,1]?
- Analyze the worst case, the best case and average cese scenarios while executing the following algorithm using appropriate examples: Divide and conquerPls do fast and i will give like for sure Solution must be in typed formConsider a voting system with 3 candidates C1,C2,C3, and 5 voters V1,V2,V3,V4,V5. The votes will be casted as cipher texts using Paillier PKC. Implement a voting scheme that uses additive homomorphic property of Paillier. (Suppose voter J votes for candidate I using the equation vote(J)= J mod 3.) Show all the steps and the final tally.