P.16.15. A thin-walled closed section beam of constant wall thickness t has the cross-section shown inFig. P.16.15. Assuming that the direct stresses are distributed according to the basic theory of bending,calculate and sketch the shear flow distribution for a vertical shear force S, applied tangentially to thecurved part of the beam.Answer: 901 = Sy(1.61 cos 0-0.80)/rSy7.3912=(0.57s² - 1.14rs +0.33²) FIGURE P.16.15شامOr310S45⁰ 245°CON

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P.16.15. A thin-walled closed section beam of constant wa Fig. P.16.15. Assuming that the direct stresses are distribut calculate and sketch the shear flow distribution for a vertic curved part of the beam. == Answer: 901 = Sy(1.61 cos 0 – 0.80)/r Sy 912 = (0.57s²-1.14rs +0.33r²)

P.16.15. A thin-walled closed section beam of constant wa Fig. P.16.15. Assuming that the direct stresses are distribut calculate and sketch the shear flow distribution for a vertic curved part of the beam. == Answer: 901 = Sy(1.61 cos 0 – 0.80)/r Sy 912 = (0.57s²-1.14rs +0.33r²)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Beams

In structural engineering, a beam is a component made of a variety of materials (including steel alloys, and wood) that can resist loads applied laterally to the beam axis. Members, elements, rafters, shafts, and purlins are all terms used to describe beams.

Question

P.16.15. A thin-walled closed section beam of constant wall thickness t has the cross-section shown in
Fig. P.16.15. Assuming that the direct stresses are distributed according to the basic theory of bending,
calculate and sketch the shear flow distribution for a vertical shear force S, applied tangentially to the
curved part of the beam.
Answer: 901 = Sy(1.61 cos 0-0.80)/r
Sy
7.3
912=
(0.57s² - 1.14rs +0.33²)

FIGURE P.16.15
شام
O
r
3
1
0
S
45⁰ 2
45°
CON

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