P1 = 31 kN and P2 = 11 kN. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. A. Determine the force in member AB, and state if the member is in tension or compression. I recived this answer for A but it was wrong!!! (answers for  AE, AF are correct) (see the pic) then I need to calculate: D. Determine the force in member BC, and state if the member is in tension or compression. E. Determine the force in member BE, and state if the member is in tension or compression. F. Determine the force in member CD, and state if the member is in tension or compression.

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter4: Coplanar Equilibrium Analysis
Section: Chapter Questions
Problem 4.153P: Repeat Prob. 4.152 assuming that the 400-kN force is applied at O instead of L.
icon
Related questions
icon
Concept explainers
Question

P1 = 31 kN and P2 = 11 kN.

Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension.

A. Determine the force in member AB, and state if the member is in tension or compression.

I recived this answer for A but it was wrong!!! (answers for  AE, AF are correct) (see the pic)

then I need to calculate:

D. Determine the force in member BC, and state if the member is in tension or compression.

E. Determine the force in member BE, and state if the member is in tension or compression.

F. Determine the force in member CD, and state if the member is in tension or compression.

Reachion at AC
Efx=0, Rax: 31KN
Eme :0
(31x4) + CRayx 6)= (11x3)
RAy:-1S-1667kし
Point ff
Sfxこ0
31KN
fre
frE:31EN (Comp)
Teas
freニ-2\KN 」E :0kN)
Point A
OKN
fAB= FAE (os0+ 31 KN >0
FAB
FAESINO+Is-167=0
fRE: -18.95KN )
O lan ()
0 53 13°
fAE : 18.95KN (T)
flom ean O
FAB-19.63KN T
Transcribed Image Text:Reachion at AC Efx=0, Rax: 31KN Eme :0 (31x4) + CRayx 6)= (11x3) RAy:-1S-1667kし Point ff Sfxこ0 31KN fre frE:31EN (Comp) Teas freニ-2\KN 」E :0kN) Point A OKN fAB= FAE (os0+ 31 KN >0 FAB FAESINO+Is-167=0 fRE: -18.95KN ) O lan () 0 53 13° fAE : 18.95KN (T) flom ean O FAB-19.63KN T
E
4 m
А
B
3 m
3 m
V P2
Transcribed Image Text:E 4 m А B 3 m 3 m V P2
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Knowledge Booster
Statics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
International Edition---engineering Mechanics: St…
International Edition---engineering Mechanics: St…
Mechanical Engineering
ISBN:
9781305501607
Author:
Andrew Pytel And Jaan Kiusalaas
Publisher:
CENGAGE L