11) calculate the moles of oxygen ( O) in the product (Show your calculation) and what is the empirical formula of the compound ? 714/Downloads/CHM%20111%20Empirical%20Formula%20.pdfD|AT1. Mass of crucible and lid (g)30 673 g2. Mass of crucible and lid (g) (optional second heating)3. Mass of crucible, lid and magnesium (g)30.896 g4. Mass of magnesium (g)0.223 gDescription of color change of pH paperChanged from green to blue(pH 6 to 9)5. Mass of crucible, lid and product (g)30.974 g6. Mass of crucible, lid and product (g) (optional second heating)7. Calculate the mass of product (g). (show your calculation)0.301 g30.974 g-30.673 g8. Calculate the mass of oxygen (g) in the product. (show your calculation)0.078 g0.301g-0.223 g9. Calculate the mass percent of magnesium and oxygen in the product74.1% Mg 25.9 %O% mg= 0.223 g/0.301 g x 100 % = 74.1 %%0 = 0.078 g /0.301 g x 100 % = 25.9 %0.0093 moles10. Calculate the moles of magnesium (show your calculation)formua: moss of magnesiummolar mass of magnesumGiven mass of magnesium = 0.223 gMole of magnesium = 0.223 g/ 24g/mol = 0.0093 moles11. Calculate the moles of oxygen (O) in the product (show your calculation)12. What is the empirical formula of the compound?Experiment: Empirical Formula

Answered: Image /qna-images/answer/c01280cd-5b6f-436b-b657-c949cef6925b.jpg

pads/CHM%20111%20Empirical%20Formula%20.pdf D|A Mass of crucible and lid (g) 30 673 g Mass of crucible and lid (g) (optional second heating) Mass of crucible, lid and magnesium (g) 30.896 g Mass of magnesium (g) 0.223 g Description of color change of pH paper Changed from green to blue (pH 6 to 9) Mass of crucible, lid and product (g) 30.974 g Mass of crucible, lid and product (g) (optional second heating) alculate the mass of product (g). (show your calculation) 0.301 g 30.974 g-30.673 g 0.078 g ulculate the mass of oxygen (g) in the product. (show your calculation) 0.301g-0.223 g Iculate the mass percent of magnesium and oxygen in the product 74.1 % Mg 25.9 % O % mg= 0.223 g/0.301 g × 100 % = 74.1 % %0 = 0.078 g /0.301 g x 100 % = 25.9 % 0.0093 moles alculate the moles of magnesium (show your calculation) ua: mobs of magnesium molar moss of magnesum ven mass of magnesium = 0.223 g ple of magnesium = 0.223 g/ 24g/mol = 0.0093 moles lculate the moles of oxygen (O) in the product (show your calculation) at is the empirical formula of the compound? 7. Experiment: Empirical Formula

pads/CHM%20111%20Empirical%20Formula%20.pdf D|A Mass of crucible and lid (g) 30 673 g Mass of crucible and lid (g) (optional second heating) Mass of crucible, lid and magnesium (g) 30.896 g Mass of magnesium (g) 0.223 g Description of color change of pH paper Changed from green to blue (pH 6 to 9) Mass of crucible, lid and product (g) 30.974 g Mass of crucible, lid and product (g) (optional second heating) alculate the mass of product (g). (show your calculation) 0.301 g 30.974 g-30.673 g 0.078 g ulculate the mass of oxygen (g) in the product. (show your calculation) 0.301g-0.223 g Iculate the mass percent of magnesium and oxygen in the product 74.1 % Mg 25.9 % O % mg= 0.223 g/0.301 g × 100 % = 74.1 % %0 = 0.078 g /0.301 g x 100 % = 25.9 % 0.0093 moles alculate the moles of magnesium (show your calculation) ua: mobs of magnesium molar moss of magnesum ven mass of magnesium = 0.223 g ple of magnesium = 0.223 g/ 24g/mol = 0.0093 moles lculate the moles of oxygen (O) in the product (show your calculation) at is the empirical formula of the compound? 7. Experiment: Empirical Formula

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter2: Basic Statistical Analysis With Excel

Section: Chapter Questions

Problem 12P

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