The second image has background info used to help solve the practice problem. Page 138 Practice Problem 5.15:Suppose you lay a thin, lightweight sheet of plywood on top of the mattress, sothat your weight is spread over all 800 spring compress? Answer: 0.65cm. ► FIGURE 5.22 Weighing a fish.E12.0 N(a) The scale stretched by aknown weightSOLUTIONSET UP You are the object in equilibrium, so start with a free-bodydiagram of yourself (Figure 5.23). Observe that the spring forces areadditive, in the sense that the total upward force they exert on yourbody is 200 times the force of each individual spring. Your body is inequilibrium under the action of the total spring force and your weight.m = 1.50 kgSOLVE For equilibrium, the total upward force of all the supportingsprings must be 800 N, so (200)k(2.6 x 10-2 m) = 800 N, andk = 154 N/m = 1.54 N/cm.w = mg(b) The scale stretched by aknown massEXAMPLE 5.15 An innerspring mattressYou have just bought an innerspring mattress that contains coil springs in a rectangular array 20 coilswide and 40 coils long. You estimate that when you lie on the mattress, your weight is supported by about200 springs (about one-fourth of the total number of springs in the mattress). You observe that the springscompress about 2.6 cm when you lie on the mattress. Assuming that your weight of 800 N is supportedequally by 200 springs, find the force constant of each spring.(c) Free-body diagramfor the fishTorFsprW = 800 NVideo Tutor SolutioA FIGURE 5.23 Free-body diagram for you on the mattress.belwia difthe rwirewasframCONTINUEDeleticrom

Answered: Image /qna-images/answer/f3cfbfaa-f5af-4ad7-a06f-5c81ecc48217.jpg

Answered: Page 138 Practice Problem 5.15: Suppose…

Page 138 Practice Problem 5.15: Suppose you lay a thin, lightweight sheet of plyw that your weight is spread over all 800 spring co

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter5: Further Applications Of Newton's Laws: Friction, Drag, And Elasticity

Section: Chapter Questions

Problem 39PE: When using a pencil eraser, you exert a vertical force of 6.00 N at a distance of 2.00 cm from the...

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Concept explainers

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).

Question

The second image has background info used to help solve the practice problem.

Page 138 Practice Problem 5.15:
Suppose you lay a thin, lightweight sheet of plywood on top of the mattress, so
that your weight is spread over all 800 spring compress? Answer: 0.65cm.

► FIGURE 5.22 Weighing a fish.
E
12.0 N
(a) The scale stretched by a
known weight
SOLUTION
SET UP You are the object in equilibrium, so start with a free-body
diagram of yourself (Figure 5.23). Observe that the spring forces are
additive, in the sense that the total upward force they exert on your
body is 200 times the force of each individual spring. Your body is in
equilibrium under the action of the total spring force and your weight.
m = 1.50 kg
SOLVE For equilibrium, the total upward force of all the supporting
springs must be 800 N, so (200)k(2.6 x 10-2 m) = 800 N, and
k = 154 N/m = 1.54 N/cm.
w = mg
(b) The scale stretched by a
known mass
EXAMPLE 5.15 An innerspring mattress
You have just bought an innerspring mattress that contains coil springs in a rectangular array 20 coils
wide and 40 coils long. You estimate that when you lie on the mattress, your weight is supported by about
200 springs (about one-fourth of the total number of springs in the mattress). You observe that the springs
compress about 2.6 cm when you lie on the mattress. Assuming that your weight of 800 N is supported
equally by 200 springs, find the force constant of each spring.
(c) Free-body diagram
for the fish
Tor
Fspr
W = 800 N
Video Tutor Solutio
A FIGURE 5.23 Free-body diagram for you on the mattress.
belwi
a dif
the r
wire
was
fram
CONTINUED
ele
tic
ro
m

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