Part 1: Use transformations to prove congruency.1. Given: CB || ED; CB= EDProve: CBF = EDF using isometric (rigid) transformations.EDF using a paragraph proof. Be sure to nameOutline the necessary transformations to prove CBF =specific sides or angles used in the transformation and any congruency statements. 1. The congruency of AMNO and AXYZ can be proven using a reflection across the line bisectingoz. However, this congruency can also be proven using geometric postulates, theorems, anddefinitions. Prove that the triangles are congruent using a two-column proof and trianglecongruency theorems.Given: L M = LXLN = LYYO = NZProve: AMNO = AXYZхMe

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Asked Feb 5, 2020
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Part 1: Use transformations to prove congruency.
1. Given: CB || ED; CB= ED
Prove: CBF = EDF using isometric (rigid) transformations.
EDF using a paragraph proof. Be sure to name
Outline the necessary transformations to prove CBF =
specific sides or angles used in the transformation and any congruency statements.
help_outline

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Part 1: Use transformations to prove congruency. 1. Given: CB || ED; CB= ED Prove: CBF = EDF using isometric (rigid) transformations. EDF using a paragraph proof. Be sure to name Outline the necessary transformations to prove CBF = specific sides or angles used in the transformation and any congruency statements.

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1. The congruency of AMNO and AXYZ can be proven using a reflection across the line bisecting
oz. However, this congruency can also be proven using geometric postulates, theorems, and
definitions. Prove that the triangles are congruent using a two-column proof and triangle
congruency theorems.
Given: L M = LX
LN = LY
YO = NZ
Prove: AMNO = AXYZ
х
Me
help_outline

Image Transcriptionclose

1. The congruency of AMNO and AXYZ can be proven using a reflection across the line bisecting oz. However, this congruency can also be proven using geometric postulates, theorems, and definitions. Prove that the triangles are congruent using a two-column proof and triangle congruency theorems. Given: L M = LX LN = LY YO = NZ Prove: AMNO = AXYZ х Me

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