PART 2:Determine the shear force acting at each of the following locations:(a) x = 0+ ft (i.e., just to the right of support A)(b) x = 14.0 ft (i,e., at point B.)(c) x = 20.5- ft (i.e., just to the left of the support C) (d) x = 20.5+ ft (i.e., just to the right of the support (C) (e)x=27.5ftNote that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. My Answers:Correct(a) V= 105.823 kips (b)V= -48.177 kips (c) V= -119.677 kips (d)V= 88 kips (e) V= 10.9998 kipsPART 3:Determine the bending moment acting at each of the following locations:(a) x = 14.0- ft (i.e., just to the left of point B.)(b) x = 14.0+ ft(i.e., just to the right of point B.)(c) x = 20.5 ft (i.e. at point C)(d)x=27.5ftNote that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. My Answers:Correct(a) M = 403.522 kips-ft(b) M = 193.522 kips-ft(c) M = -352.0035 kips-ft(d) M = -5.5049 kips-ftI do not know how to answer part 4, please help. Part 1For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment Mfor any location in the beam. (Place the origin at point A.) Let a=14.0 ft, b-6.5 ft, c= 8.0 ft, w = 11 kips/ft and M = 210 kip-ft.Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequentparts of this GO exercise.ACorrectAnswers:Ay =bCalculate the reaction forces A, and Cy acting on the beam. Positive values for the reactions are indicated by the directions of thered arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)Cy=105.823W207.677aWMaMBkipskipsCbCCyCCX Part 4Use your shear-force and bending-moment diagrams to determine the maximum positive bending moment, Mmax, pos, themaximum negative bending moment, Mmax, neg, and their respective locations, Xmax, pos and Xmax, neg. When entering your answersfor the maximum bending moments, use the shear-force and bending-moment sign conventions detailed in Section 7.2. Themaximum negative bending moment is the negative moment with the largest absolute value. Enter the maximum negativebending moment as a negative value.Answers:Mmax, posMmax, neg=iikips-ft Xmax, poskips-ft Xmax, negiiftft

For the simply supported beam subjected to the loading shown, derive equations for the shear force V…

Answered: Part 4 Use your shear-force and…

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter6: Beams And Cables

Section: Chapter Questions

Problem 6.42P: For the beam AB shown in Cases 1 and 2, derive and plot expressions for the shear force and bending...

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PART 2: Determine the shear force acting at each of the following locations: (a) x = 0+ ft (i.e., just to the right of support A) (b) x = 14.0 ft (i,e., at point B.) (c) x = 20.5- ft (i.e., just to the left of the support C) (d) x = 20.5+ ft (i.e., just to the right of the support (C) (e)x=27.5ft Note that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. My Answers: Correct (a) V= 105.823 kips (b)V= -48.177 kips (c) V= -119.677 kips (d)V= 88 kips (e) V= 10.9998 kips PART 3: Determine the bending moment acting at each of the following locations: (a) x = 14.0- ft (i.e., just to the left of point B.) (b) x = 14.0+ ft(i.e., just to the right of point B.) (c) x = 20.5 ft (i.e. at point C) (d)x=27.5ft Note that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. My Answers: Correct (a) M = 403.522 kips-ft (b) M = 193.522 kips-ft (c) M = -352.0035 kips-ft (d) M = -5.5049 kips-ft I do not know how to answer part 4, please help.

Part 1
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M
for any location in the beam. (Place the origin at point A.) Let a=14.0 ft, b-6.5 ft, c= 8.0 ft, w = 11 kips/ft and M = 210 kip-ft.
Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent
parts of this GO exercise.
A
Correct
Answers:
Ay =
b
Calculate the reaction forces A, and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the
red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)
Cy=
105.823
W
207.677
a
W
M
a
M
B
kips
kips
C
b
C
Cy
C
C
X

Part 4
Use your shear-force and bending-moment diagrams to determine the maximum positive bending moment, Mmax, pos, the
maximum negative bending moment, Mmax, neg, and their respective locations, Xmax, pos and Xmax, neg. When entering your answers
for the maximum bending moments, use the shear-force and bending-moment sign conventions detailed in Section 7.2. The
maximum negative bending moment is the negative moment with the largest absolute value. Enter the maximum negative
bending moment as a negative value.
Answers:
Mmax, pos
Mmax, neg
=
i
i
kips-ft Xmax, pos
kips-ft Xmax, neg
i
i
ft
ft

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