Part A A downward force of magitude SNisexerted on the book by the force of O he table. O gavity. O inertia. Submit RecunstAnswer • Part B An upward force of magnitude is exerted on theby the table. O GN/able O SN/able O SN/book O ON/book Submit • Part C
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- At one moment during a walk around the block, there are four forces exerted upon Fido - a 10.0 kg dog. The forces are: Fapp = 67.0 N at 30.0° above the horizontal (rightward and upward)Fnorm = 64.5 N, upFfrict = 27.6 N, leftFgrav = 98 N, down Resolve the applied force (Fapp) into horizontal and vertical components, then add the forces up as vectors to determine the net force.1.2.5-kg tourist climbs the stairs to the top of the WashingtonMonument, which is 555 ft high. How far does the Earth movein the opposite direction as the tourist climbs?Explain and labled.Is it possible for an object at rest to have only a single force actingon it? If your answer is yes, provide an example. If your answer isno, explain why not.
- A 50 kg object is acted upon by two forces (in N) F, = - 107 +50 7 and F, = 10 7 +50 7 What is the magnitude of its acce.If a man weighs 850N on the Earth, what would he weigh on Jupiter, where the free-fall acceleration is 25.9 m/s2? A 00-kg object undergoes an acceleration given by = (4.00 î + 9.00 ĵ) m/s2. Find the resultant force and its magnitude acting on the object.In the Jurassic Park sequel, The Lost World, a man tries to keep alarge vehicle from going over a cliff by connecting a cable from hisJeep to the vehicle. The man then puts the Jeep in gear and spinsthe rear wheels. Do you expect that spinning the tires will increasethe force exerted by the Jeep on the vehicle? Why or why not?
- An athlete whirls a 6.41 kg hammer tied tothe end of a 1.3 m chain in a simple horizontalcircle where you should ignore any verticaldeviations. The hammer moves at the rate of1.64 rev/s.What is the tension in thechain? Assume his arm length is includedin the length given for the chain.When the Moon is directly overhead at sunset, the force by Earth on the Moon, FEM , is essentially at 90° to the force by the Sun on the Moon, FSM , as shown below. Given that FEM = 1.98 × 1020 N and FSM = 4.36 × 1020 N, all other forces on the Moon are negligible, and the mass of the Moon is 7.35 × 1022 kg, determine the magnitude of the Moon’s acceleration.Which is larger, the graviational force of the sun on the earth (Fse) or the gravitational force of the earth on the sun (Fes)? a) Fse > Fes b) Fse < Fes c) Fse = Fes
- A driver who does not wear a seatbelt continues to move forward with a speed of 18.0 m>s (due to inertia) until somethingsolid like the steering wheel is encountered. The driver now comesto rest in a much shorter distance—perhaps only a few centimeters. Find the magnitude of the net force acting on a 65.0-kg driverwho is decelerated from 18.0 m>s to rest in 5.00 cm.A. 3240 N B. 1.17 * 104NC. 2.11 * 105N D. 4.21 * 105N15. Calculate the tension force on the rope AD. a. 30N b. 90N c. 180N d. 294N e. None of the aboveFind the acceleration of the masses where M = 4 Kg and m = 2 Kg, μk = 0.2. find the angle using tan angle =coefficent of friction