Part AA long pair of insulated wires serves to conduct 23.0 Aof dc current to and from an instrument.If the wires are of negligible diameter but are 2.8 mm apart, what is the magnetic field 10.0 cm from their midpoint,in their plane (Figure 1)?Express your answer using two significant figures.0 ΑΣφ?Bnet =TSubmitPrevious Answers Request AnswerX Incorrect; Try Again; 4 attempts remainingFigure1 of 1▼Part BCompare to the magnetic field of the Earth of 5.0 × 10–5 T.Express your answer using two significant figures.10.0 cmΑΣφBnetВBarth2.8 mmSubmitRequest Answer

Current (I) = 23.0 A distance between the two wires (d) = 2.8 mm= 0.0028 mdistance of observation…

Part A A long pair of insulated wires serves to conduct 23.0 A of dc current to and from an instrument. If the wires are of negligible diameter but are 2.8 mm apart, what is the magnetic field 10.0 cm from their midpoint, in their plane (Figure 1)? Express your answer using two significant figures. Bnet = Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Figure 1 of 1 Part B Compare to the magnetic field of the Earth of 5.0 × 10-5 T. Express your answer using two significant figures. 10.0 cm V ΑΣφ ? Bnet %3D BEarth 2.8 mm Submit Request Answer

Part A A long pair of insulated wires serves to conduct 23.0 A of dc current to and from an instrument. If the wires are of negligible diameter but are 2.8 mm apart, what is the magnetic field 10.0 cm from their midpoint, in their plane (Figure 1)? Express your answer using two significant figures. Bnet = Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Figure 1 of 1 Part B Compare to the magnetic field of the Earth of 5.0 × 10-5 T. Express your answer using two significant figures. 10.0 cm V ΑΣφ ? Bnet %3D BEarth 2.8 mm Submit Request Answer

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter24: Magnetic Fields

Section: Chapter Questions

Problem 83A

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Similar questions

Unreasonable results A charged particle having mass 6.641027kg (that of a helium atom) moving at 8.70105m/s perpendicular to a 1.50-T magnetic field travels in a circular path of radius 16.0 mm. (a) What is the charge of the particle? (b) What is unreasonable about this result? (c) Which assumptions are responsible?
(a) An oxygen16 ion with a mass at 2.661026kg travels at 5.00106m/s perpendicular to a 1.20T magnetic field, which makes it move in a circular arc with a 0.231-m radius. What positive charge is on the ion? (b) What is the radio of this charge to the charge of an electron? (c) Discuss why the radio found in (b) should be an integer.
A charged particle is moving perpendicular to a magnetic field in a circle with a radius r. (i) An identical particle enters the field, with v perpendicular to B, but with a higher speed than the first particle. Compared with the radius of the circle for the first particle, is the radius of the circular path for the second particle (a) smaller, (b) larger, or (c) equal in size? (ii) The magnitude of the magnetic field is increased. From the same choices, compare the radius of the new circular path of the first particle with the radius of its initial path.
Explain why the magnetic field would not be unique (that is, not have a single value) at a point in space where magnetic field lines might cross. (Consider the direction of the field at such a point.)
A long, vertical, metallic wire carries downward electric current. (i) What is the direction of the magnetic field it creates at a point 2 cm horizontally east of the center of the wire? (a) north (b) south (c) east (d) west (e) up (ii) What would be the direction of the field if the current consisted of positive charges moving downward instead of electrons moving upward? Choose from the same possibilities as in part (i).
An electron in a TV CRT moves with a speed at 6.00107m/s, in a direction perpendicular to the Earth’s field, which has a strength of 5.00105T. (a) What strength electric field must be applied perpendicular to the Earth’s field to make the election moves in a straight line? (b) If this is done between plates separated by 1.00 cm, what is the voltage applied? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a correction.)
Unreasonable Results A surveyor 100 m from a long straight 200-kV DC power line suspects that its magnetic field may equal that of the Earth and affect compass readings. (a) Calculate the current in the wire needed to create a 5.00105T field at this distance. (b) What is unreasonable about this result? (c) Which assumption or premise is responsible?
A very large parallel-plate capacitor has uniform charge per unit area + on the upper plate and on the lower plate. The plates are horizontal, and both move horizontally with speed v to the right. (a) What is the magnetic field between the plates? (b) What is the magnetic field just above or just below the plates? (c) What are the magnitude and direction of the magnetic force per unit area on the upper plate? (d) At what extrapolated speed v will the magnetic force on a plate balance the electric force on the plate? Suggestion: Use Amperes law and choose a path that closes between the plates of the capacitor.
The magnetic field at all points within the cylindrical region whose cross-section is indicated in the accompanying figure starts at 1.0 T and decreases uniformly to zero in 20 s. What is the electric field (both magnitude and direction) as a function of r, the distance from the geometric center of the region?
Unreasonable Results Frustrated by the small Hall voltage obtained in blood flow measurements, a medical physicist decides to increase the applied magnetic field strength to get a 0.500V output for blood moving at 30.0 cm/s in a 1.50cmdiameter vessel. (a) What magnetic field strength is needed? (b) What is unreasonable about this result? (c) Which premise is responsible?