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K = 1.8x10-28 Previous Answers v Correct Correct answer is shown. Your answer 1.78-10-2 = 1.78x1028 was either rounded differently or used a different number of significant figures than required for this part. • Part C MnO2(s) +4 H*(ag) + Cu(s) → Mn²+ (ag) +2 H2O(!) + Cu²*(aq) Express your answer using two significant figures. K= 2.0 • 1045 Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining

K = 1.8x10-28 Previous Answers v Correct Correct answer is shown. Your answer 1.78-10-2 = 1.78x1028 was either rounded differently or used a different number of significant figures than required for this part. • Part C MnO2(s) +4 H*(ag) + Cu(s) → Mn²+ (ag) +2 H2O(!) + Cu²*(aq) Express your answer using two significant figures. K= 2.0 • 1045 Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.101QE: At 298 K, the solubility product constant for PbC2O4 is 8.5 1010, and the standard reduction...
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pls.helpp partC

Part A Calculate the equilibrium constant for each of the reactions at 25 °C. Pb?+ (ag) + Zn(s)→ Pb(s) + Zn²+ (ag) Standard Electrode Potentials at 25 °C Express your answer using three significant figures. Reduction Half-Reaction E° (V) K = 2.04x1021 Pb2+ (ag) + 2 e →Pb(s) → Zn(s) I2(s) + 2 e →2 I¯(aq) Cl2 (g) + 2 e → 2 Cl¯ (aq) MnO2(s) +4 H+(aq) +2 e¯ → Mn²+(aq) + 2 H2O(1) -0.13 Zn2+ (aq) + 2 e¯ -0.76 Submit Previous Answers 0.54 1.36 Correct 1.21 Correct answer is shown. Your answer 2.09-10²1 = 2.09x1021 was either rounded differently or used a different number of significant figures than required for this part. Cu?+(ag) + 2 e¯ → Cu(s) 0.16 Part B I2(s) + 2 Cl¯ (aq) → 2I- (aq) + Cl2(g) Express your answer using two significant figures. K = 1.8x10-28 Submit Previous Answers v Correct Correct answer is shown. Your answer 1.78-10-28 = 1.78x10-28 was either rounded differently or used a different number of significant figures than required for this part. Part C MnO2 (s) +4 H†(aq) + Cu(s) → Mn²+ (aq) + 2 H2O(1) + Cu²+ (aq) Express your answer using two significant figures. ? K = 2.0 • 1045 Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining
Transcribed Image Text:Part A Calculate the equilibrium constant for each of the reactions at 25 °C. Pb?+ (ag) + Zn(s)→ Pb(s) + Zn²+ (ag) Standard Electrode Potentials at 25 °C Express your answer using three significant figures. Reduction Half-Reaction E° (V) K = 2.04x1021 Pb2+ (ag) + 2 e →Pb(s) → Zn(s) I2(s) + 2 e →2 I¯(aq) Cl2 (g) + 2 e → 2 Cl¯ (aq) MnO2(s) +4 H+(aq) +2 e¯ → Mn²+(aq) + 2 H2O(1) -0.13 Zn2+ (aq) + 2 e¯ -0.76 Submit Previous Answers 0.54 1.36 Correct 1.21 Correct answer is shown. Your answer 2.09-10²1 = 2.09x1021 was either rounded differently or used a different number of significant figures than required for this part. Cu?+(ag) + 2 e¯ → Cu(s) 0.16 Part B I2(s) + 2 Cl¯ (aq) → 2I- (aq) + Cl2(g) Express your answer using two significant figures. K = 1.8x10-28 Submit Previous Answers v Correct Correct answer is shown. Your answer 1.78-10-28 = 1.78x10-28 was either rounded differently or used a different number of significant figures than required for this part. Part C MnO2 (s) +4 H†(aq) + Cu(s) → Mn²+ (aq) + 2 H2O(1) + Cu²+ (aq) Express your answer using two significant figures. ? K = 2.0 • 1045 Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining
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