Part A - Support Reactions Determine the support reactions for the beam shown in the figure below. 5 kN/m 70 kNI 20 SH SUPAYA SA SHOP 140 kN 10 KN B 1 m 2 m 2 m 2 m Express your answers, separated by commas, to three significant figures. 1 m
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- F= 20 kN; M=6 kN•m; q=16 kN/m^2; a=2; b=5; c=1; d=2; 1. calculate reactions 2. calculate VNM (vertical, axial, transverse) 3. make the graphical representation of (VNM) diagramsDetermine the magnitude of the horizontal reaction (N) at A if P = 255 N and Q = 1990 N. Let x = 2.45 m, y = 2.56 m, and z = 2.06 m. Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of the horizontal reaction at A: use R if to the right and L if to the left.Show complete and detailed solution. Show FBD of the figure. What is the smallest mass of B to make the system in equilibrium while neglecting the friction between the string and the ramp? Mass of Block A = 45kg Coefficient of Block A, Block B, and Ramp C = 0.10
- Problem 3. Determine the following unknowns on the beam shown below using Conjugate-Beam Method. Consider 250 mm x 250 mm section and E = 200 GPa. Show complete and organized solution. Round-off your answers to two decimal places. QUESTIONS: a. Vertical Reaction at C in kN. b. Moment Reaction at C in kN-m. c. Deflection at point B in mm. d. Maximum deflection on the beam in mm GIVEN: a. 4.2 b. 19.0 c. 85A 4-ft-diameter log (sg. = 0.82) divides two shallow water as shown in the figure. Compute the vertical reaction at point C, if the log is 12 ft long. CHOICES A.) 658.68 B.) 568.88 C.) 856.86 D.) 865.65For equation 1, RB+RA=1500. So how did you get RB=2580-50700, RB=-48120 lb ? Also for moment at point B, if 1500 lb-ft is clockwise. How is it positive in moment at point B?
- Problem 2. Determine the following unknowns on the beam shown below using Area-Moment Method. Consider 150 mm x 150 mm section and E = 80 GPa. Show complete and organized solution. Round-off your answers to two decimal places. QUESTIONS: a. Vertical Reaction at B in kN. b. Moment Reaction at A in kN-m. c. Deflection at point C in mm. d. Deflection at midspan of AB in mm. GIVEN: a. 3.1 b. 18.0 c. 20Use Moment Distribution Method determine the member end moments of the beam of the rectangular cross section shown in Figure 11.10a. Assume that support B settles 2 cm. The modulus of elasticity and the moment of inertia of the beam are E = 210,000 N/mm2 and 4.8 × 104 mm,4 respectively. Hint final answer: MAB= 0 MBA= 141.9 kn.m MBC= -141.9 kn.m MCB= 81.26 kn.mDetermine the resultant of the vertical thrusts on the sphere shown in the figure for the data: d=0.6m; R=0.5m;h=4m.
- Consider the frame shown in (Figure 1). Suppose that F1 = 3.5 kN. a) Determine the x and y components of the force that the pin at B exerts on the frame using scalar notation. b) Determine the x and y components of the force that the pin at A exerts on the frame using scalar notation. Express your answers in kilonewtons to three significant figures. Enter your answers separated by a comma.Problem 9. For the tank shown in the figure, the following dimensions apply: h1=3.00m h2=4.50m w=2.50m y=9.81kN/m^3. Compute the horizontal component of the resultant force on the curved surfaces.a. 168.0 kNb. 158.0 kNc. 148.0 kNd. 138.0 kNe. 128.0 kNf. 118.0 kNThe 14.6 lb lever OA with 9.6 in radius of gyration about O is initially at rest in the vertical position (?= 90°) where the attached spring of stiffness k = 4.3 lb/in is unstretched. Calculate the constant moment M applied to the lever through its shaft at O which will give the lever an angular velocity ? = 5.9 rad/sec as the lever reaches the horizontal position ? = 0.