please answer all as they are part of 1 question but different questions,,. Part AThe Arrhenius equation shows the relationship between the rate constant k andthe temperature T in kelvins and is typically written asThe activation energy of a certain reaction is 36.3 kJ/mol . At 22 °C , the rate constant is 0.0180s¬1 . At what temperature in degrees Celsius would this reaction go twice as fast?k = Ae-Ea/RTwhere R is the gas constant (8.314 J/mol · K), A is a constant called thefrequency factor, and Ea is the activation energy for the reaction.Express your answer with the appropriate units.However, a more practical form of this equation isHA?In=( -)k2k1Ea11RTT,which is mathmatically equivalent toT, =ValueUnitsk1E.Ink2TTRwhere ki and k2 are the rate constants for a single reaction at two differentabsolute temperatures (T1 and T2 ).Part BGiven that the initial rate constant is 0.0180s- at an initial temperature of 22 °C, what would the rate constant be at a temperature of 140. °C for the same reaction described in Part A?Express your answer with the appropriate units.?k2 =ValueUnitsSubmitRequest Answer

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Part A The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k = Ae E/RT where Ris the gas constant (8.314 J/mol - K), A is a constant called the frequency factor, and E, is the activation energy for the reaction. The activation energy of a certain reaction is 36.3 kJ/mol. At 22 °C, the rate constant is 0.0180s. At what temperature in degrees Celsius would this reaction go twice as t Express your answer with the appropriate units. However, a more practical form of this equation is In 3(뉴 ) T = Value Units which is mathmatically equivalent to where ki and kz are the rate constants for a single reaction at two different absolute temperatures (T and T2). Part B Given that the initial rate constant is 0.0180s at an initial temperature of 22 °C, what would the rate constant be at a temperature of 140. °C for the same reaction described Express your answer with the appropriate units. kz = Value Units Submit Request Answer

Part A The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k = Ae E/RT where Ris the gas constant (8.314 J/mol - K), A is a constant called the frequency factor, and E, is the activation energy for the reaction. The activation energy of a certain reaction is 36.3 kJ/mol. At 22 °C, the rate constant is 0.0180s. At what temperature in degrees Celsius would this reaction go twice as t Express your answer with the appropriate units. However, a more practical form of this equation is In 3(뉴 ) T = Value Units which is mathmatically equivalent to where ki and kz are the rate constants for a single reaction at two different absolute temperatures (T and T2). Part B Given that the initial rate constant is 0.0180s at an initial temperature of 22 °C, what would the rate constant be at a temperature of 140. °C for the same reaction described Express your answer with the appropriate units. kz = Value Units Submit Request Answer

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter13: Chemical Kinetics

Section: Chapter Questions

Problem 13.99QE

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