Please answer the question Part B please The rate of a chemical reaction depends on theconcentrations of the reactants. Let's consider thegeneral reaction between A and B:aA + 6B = cC + dDThe dependence of the reaction rate on theconcentration of each reactant is given by theequation called the rate law:rate = k[A]" [B]"where k is a proportionality constant called the rateconstant. The exponent m determines the reactionorder with respect to A, and n determines thereaction order with respect to B. The overallreaction order equals the sum of the exponents (т+ n).For example, if m = 2 and n = 2 thenrate = k[A]² [B]² and the overall reaction order is2+2 = 4.The reaction orders are experimentally determinedand usually not related to the reactionstoichiometric coefficients a and b. Consider the reaction of ethyl acetate with sodium hydroxide:CH;COOC,H; (aq) + NaOH(aq) = CH;COONA(aq) + C,H;OH(aq)The reaction is first order in NaOH and second order overall. What is the rate law?• View Available Hint(s)k[CH3 COOC2H5]* [NaOH]?rate == k[CH3COOC2H5][NaOH]?= k[N2OH]rate =k[CH3COOC,H;]= k[CH3 COOC2H;][NaOH]= k[CH3COOC2H5]° [NaOH]SubmitPrevious AnswersCorrectThe reaction order exponents indicate how sensitive the rate is to changes in the concentrations of reactants. For simple reactions, the exponents are usually small positive integers. For more complex reaction, the exponents can be negative, zero, or even fractional. When the order iszero, the rate in independent of the concentration of the reactant. When the order is negative, the rate decreases as the concentration increases.For this case, first order in CH3 COOC2H5 means that the reaction rate depends linearly on the concentration of CH3COOC2H5 . For example, if (CH3COOC2H5] is doubled, the rate doubles (increases by a factor of 2). The same is true for NaOH.Part BThe reaction of ethyl acetate with sodium hydroxide,CHЗСOОС2Н5 (аq) + NaOH(aq) 3 CHзСОONa(aq) + CәHsОН(аq)is first order in CH3 COOC2H; and first order in NaOH. If the concentration of CH3 COOC2H; was increased by half and the concentration of NaOH was increased by four, by what factor would the reaction rate increase?Express your answer numerically.• View Available Hint(s)Templates Symbols undo regdo Teset keyboard shortcuts helpPesat

Rate of the reaction is the speed of the reaction per unit time.

• rate = k(CH3 CooC,Hs][NAOH] O rate = k(CH; COOC;Hs]*[N2OH] Submit Previous Answers v Correct The reaction order exponents indicate how sensitive the rate is to ch zero, the rate in independent of the concentration of the reactant. Wheo in the concentrations of reactants. For simple reactions, the exponents are usually small positive integers. For more complex reaction, the exponents can be negative, zero, or even fractional. When the order is the order is negative, the rate decreases as the concentration increases. For this case, first order in CH3 COOC2H5 means that the reaction rate depends linearly on the concentration of CH3 COOC;Hs. For example, if (CH3COOC2H5] is doubled, the rate doubles (increases by a factor of 2). The same is true for NaOH. Part B The reaction of ethyl acetate with sodium hydroxide, CH3COOC,Hs (aq) + NaOH(aq) = CH3COONA(aq) + C2H5OH(aq) is first order in CH3COOC;Hs and first order in NAOH. If the concentration of CH3 COOC2H, was increased by half and the concentration of NaOH was increased by four, by what factor would the reaction rate increase? Express your answer numerically. > View Available Hint(s) Templates Symbols undo rego feset keyboard shortcuts Help

• rate = k(CH3 CooC,Hs][NAOH] O rate = k(CH; COOC;Hs]*[N2OH] Submit Previous Answers v Correct The reaction order exponents indicate how sensitive the rate is to ch zero, the rate in independent of the concentration of the reactant. Wheo in the concentrations of reactants. For simple reactions, the exponents are usually small positive integers. For more complex reaction, the exponents can be negative, zero, or even fractional. When the order is the order is negative, the rate decreases as the concentration increases. For this case, first order in CH3 COOC2H5 means that the reaction rate depends linearly on the concentration of CH3 COOC;Hs. For example, if (CH3COOC2H5] is doubled, the rate doubles (increases by a factor of 2). The same is true for NaOH. Part B The reaction of ethyl acetate with sodium hydroxide, CH3COOC,Hs (aq) + NaOH(aq) = CH3COONA(aq) + C2H5OH(aq) is first order in CH3COOC;Hs and first order in NAOH. If the concentration of CH3 COOC2H, was increased by half and the concentration of NaOH was increased by four, by what factor would the reaction rate increase? Express your answer numerically. > View Available Hint(s) Templates Symbols undo rego feset keyboard shortcuts Help

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter11: Chemical Kinetics: Rates Of Reactions

Section11.7: Reaction Mechanisms

Problem 11.12E

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