Part CRank the automobiles based on the magnitude of the force needed to stop them, from largest to smallestRank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below.> View Avallable Hint(s)Reset Help500 kg500 kg4000 kg1000 kg1000 kg2000 kg10 m/s20 m/s5 m/s20 m/s10 m/s5 m/slargestsmallestO The correct ranking cannot be determined.SubmitProvide Feedback• PreviousMacBook Pro0S earch or ty pe URL96568RYFGHBM

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Description: Part CRank the automobiles based on the magnitude of the force needed to stop them, from largest to smallestRank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below.> View Ava

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Part C Rank the automobiles based on the magnitude of the force needed to stop them, from largest to smallest Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below. > View Available Hint(s) Reset Help 500 kg 500 kg 4000 kg 1000 kg 1000 kg 2000 kg 10 m/s 5 m/s 20 m/s 10 m/s 5 m/s 20 m/s

Part C Rank the automobiles based on the magnitude of the force needed to stop them, from largest to smallest Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below. > View Available Hint(s) Reset Help 500 kg 500 kg 4000 kg 1000 kg 1000 kg 2000 kg 10 m/s 5 m/s 20 m/s 10 m/s 5 m/s 20 m/s

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter4: The Laws Of Motion

Section4.4: Newton's Third Law

Problem 4.4QQ: A small sports car collides head-on with a massive truck. The greater impact force (in magnitude)...

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Jogging on hard surfaces with insufficiently padded shoes produces large forces in the feet and legs. (a) Calculate the magnitude of the force needed to stop the downward motion of a jogger's leg, if his leg has a mass of 13.0 kg, a speed of 6.00 m/s, and stops in a distance of 1.50 cm. (Be certain to include the weight of the 75.0-kg jogger's body.) (b) Compare this force with the weight of the jogger.
Figure 4.39 shows Superhero and Trusty Sidekick hanging motionless from a rope. Superhero's mass is 90.0 kg, while Trusty Sidekick's is 55.0 kg, and the mass of the rope is negligible. (a) Draw a free-body diagram of the situation showing all forces acting on Superhero, Trusty Sidekick, and the rope. (b) Find the tension in the rope above Superhero. (c) Find the tension in the rope between Superhero and Trusty Sidekick. Indicate on your free-body diagram the system of interest used to solve each part. Figure 4.39 Superhero and Trusty Sidekick hang motionless on a rope as they try to figure out what to do next. Will the tension be the same everywhere in the rope?
A boxer breaks his hand by punching another boxers jaw. How is it possible to break your hand when you exert such a force?
A small sports car collides head-on with a massive truck. The greater impact force (in magnitude) acts on (a) the car, (b) the truck, (c) neither, the force is the same on both. Which vehicle undergoes the greater magnitude acceleration? (d) the car, (e) the truck, (f) the accelerations are the same.
A baseball catcher is performing a stunt for a television commercial. He will catch a baseball (mass 145 g) dropped from a height of 60.0 m above his glove. His glove stops the ball in 0.0100 s. What is the force exerted by his glove on the ball?
A 5.00-kg block is placed on top of a 10.0-kg block (Fig. P5.50). A horizontal force of 45.0 N is applied to the 10-kg block, and the 5-kg block is tied to the wall. The coefficient of kinetic friction between all moving surfaces is 0.200. (a) Draw a free-body diagram for each block and identify the action-reaction forces between the blocks. (b) Determine the tension in the string and the magnitude of the acceleration of the 10-kg block. Figure P5.50
Train Collision and Newtons First Law A group of college students discusses the train collision case study. Use Newtons first law to decide which underlined statements are correct and which are false. Explain your answers. Shannon: This newspaper says that the people who got really hurt were either standing up or sitting in a forward-facing seat. Those people got thrown forward when the train stopped. Avi: Thats why there are seat belts in cars. If you get into a crash, the force can throw you through the windshield. Cameron: There is no force that throws you through the windshield. You fly through the windshield because you are already moving and it would take a force to stop you from going forward. Thats why theres a seat belt. Avi: That doesnt make sense. Because then you would need a force to stop you from flying through the windshield even when you just stop slowly at a red light. Cameron: Thats right, but when you slow down slowly, you dont need such a big force and the car seat can take care of it. Shannon: The seat? I dont think a seat can exert a force. It cant move on its own or hold you. Thats why the people who were sitting forward on the train were hurt. The people who were sitting backward had the back of the seat to block them.
Assume the resistive force acting on a speed skater is proportional to the square of the skaters speed v and is given by f = kmv2, where k is a constant and m is the skaters mass. The skater crosses the finish line of a straight-line race with speed vi and then slows down by coasting on his skates. Show that the skaters speed at any time t after crossing the finish line is v(t) = vi/(1 + ktvi).
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Assume the resistive force acting on a speed skater is proportional to the square of theskater’s speed v and is given by f = −kmv2, where k is a constant and m is the skater’smass. The skater crosses the finish line of a straight-line race with speed vi and thenslows down by coasting on his skates. Show that the skater’s speed at any time t aftercrossing the finish line is v(t) = vi/(1 + ktvi).
The Johnsons just received a heavy package (perhaps a treadmill) in the mail that they ordered from a popular online shopping website. It's so heavy that they had to push it across their carpeted floor since it was too heavy to lift. The item weighs 92.3 kg and it's packaged in cardboard. The coefficient of friction between the cardboard and their carpet is 0.71. They're a team, and they all push the huge package across their living room at a constant speed. How much collective force do they have to use to push the package across the living room at a constant speed of 0.07m / s Use the approximation g = 10m / (s^ 2)
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