PART D. RC Circuit A resistor and capacitor are connected in series. The resistor has a resistance of 20-M2, the capacitor has a capacitance of 2.0-pF, and they are connected to a 12-V battery. Before the switch is closed, the capacitor is uncharged. V R (a) What is the maximum current through the resistor? (b) What will be the maximum charge on the capacitor? (c) Calculate for the time constant. (d) What fraction of charge is stored on the plates at time t= 30 s? (e) What fraction of charge is stored on the plates at time t= 100 s?

Q: Find the current I through the circuit. I=    (mA). Find the voltage across each resistor. Give your…

A: Applying kirchoffs loop rule, 12-(10+20+10+10+10)*10^3 * I -24 =0   I=-12(60×103)=-2×10-4A=0.2mA

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A: R1 = 13 ohm R2 = 6 ohm R3 = 7.7 ohm R4 = 11 ohm E = 15 volts

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A: Solution:-

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A: Given, Voltage V = 1 V Resistance R1 = 9 ohm Current I1 = 1 A Resistance R2 = 7 ohm

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A: Given data: The resistances are, R1=11 ΩR2=6.5 ΩR3=6.2 ΩR4=12 Ω The emf of battery is ε=18 V.

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A: Given that V  = 12 V R1 = 1 Ohm V2R = 4 V P3R  = 12 W

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A: Given values: Resistors: R1=11ΩR2=6.2ΩR3=7.8ΩR4=11Ω Voltage ε=18 V

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A: The question asks certain facts about charging/discharging a capacitor.

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A: Answer :  Correct answer is  ∆Vc= E .

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A: (a) Calculate the current flowing in the circuit. i=VR=4 Volts3 Ohms=43 A

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A: Here Time constant of circuit is given by τ=ReqCeqReq=4×24+2kΩReq=86=43kΩCeq=C1+C2=3+6=9μF