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Part of a proof is shown. Given: ZFBC= ¿FCB A B DE ZGCD LGDC CF || DG Prove: BF ||CG G Statement Reason |1. 2FBC = LFCB |1. Given 2. 2GCD 2GDC 2. Given 3. CF || DG 3. Given 4. 4. 5. 5. Substitution 6. BF || CG 6. hich of these could be used for Statement 4 of the proof? ZBCF = ¿CDG O LFCG LGDE © LBFC LCGD ZFCG LCGD

Part of a proof is shown. Given: ZFBC= ¿FCB A B DE ZGCD LGDC CF || DG Prove: BF ||CG G Statement Reason |1. 2FBC = LFCB |1. Given 2. 2GCD 2GDC 2. Given 3. CF || DG 3. Given 4. 4. 5. 5. Substitution 6. BF || CG 6. hich of these could be used for Statement 4 of the proof? ZBCF = ¿CDG O LFCG LGDE © LBFC LCGD ZFCG LCGD

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter2: Parallel Lines
Section2.CT: Test
Problem 3CT: To prove a theorem of the form "If P, then Q" by the indirect method, the first line of the proof...
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Part of a proof is shown. Given: 2FBC = ¿FCB DE ZGCD LGDC CF || DG Prove: BF ||CG Statement Reason 1. ZFBC = LFCB 1. Given 2. ZGCD LGDC 2. Given 3. CF || DG 3. Given 4. |4. 5. 5. Substitution 6. BF || TG 6. Which of these could be used for Statement 4 of the proof? A A LBCF = LCDG O LFCG LGDE © ZBFC 2CGD O LFCG ¿CGD
Transcribed Image Text:Part of a proof is shown. Given: 2FBC = ¿FCB DE ZGCD LGDC CF || DG Prove: BF ||CG Statement Reason 1. ZFBC = LFCB 1. Given 2. ZGCD LGDC 2. Given 3. CF || DG 3. Given 4. |4. 5. 5. Substitution 6. BF || TG 6. Which of these could be used for Statement 4 of the proof? A A LBCF = LCDG O LFCG LGDE © ZBFC 2CGD O LFCG ¿CGD
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