particle traveling along a straight line is a=- si m/s where s is in meters. If v=0, s=4.8 when t=0, determine the partícle's velocity at s=9
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- The acceleration of a particle along a straight line is defined by a = (2t - 9) m/s2, where t is in seconds. At t = 0, s = 1 m and v = 10 m/s. When t = 9s, determine (a) the particle’s position, (b) the total distance traveled, and (c) the velocityFind how far an airplane will move in landing, if in t seconds after touching the ground its speed in feet per second is given by the equation. v= 180 – 18t. (hint: take v=0, C=0 ).The velocity of a particle traveling in a straight line is given by v = (2t - 6t ²) m/s, where t is in seconds. If s = 0 when t = 0, determine the particle’s (a) position and (b) acceleration when t = 16 s.
- Starting from rest, a particle moving in a straight line has an acceleration of a = (2t — 6) m/s2 where t is in seconds. What is the particle's position when t = 11 s?The acceleration of a particle moving along a straight line is given by? = 6? where a is in m/s2 and t is in seconds. At t = 0, the particle has avelocity of 10 m/s. Find the distance, in m, traveled by the particle after5 seconds.1. The velocity of a rocket is tabulated as follows:Use backward, forward, and central differences to approximate the acceleration of the rocket at times t=1.0s and t=1.75s.
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