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P(DeathTrend) = 45/90 = 0.500 - P(AdultvacTrend) = 45/90 = 0.500 - P(increasing) = 43/90 = 0.478 - P(Decreasing) = 46/90- 0.511 P(Same) = 1/90 = 0.0111 P(DeathTrendu Increasing) = (20 + 22+ 24+ 1) = 68/90 =0. P(DeathTrendu Decreasing) = (20+24 +1+22) = 67/90 = 0 - P(DeathTrend U Same) (20 + 24 +1+ 0) = 45/90 = 0.500

P(DeathTrend) = 45/90 = 0.500 - P(AdultvacTrend) = 45/90 = 0.500 - P(increasing) = 43/90 = 0.478 - P(Decreasing) = 46/90- 0.511 P(Same) = 1/90 = 0.0111 P(DeathTrendu Increasing) = (20 + 22+ 24+ 1) = 68/90 =0. P(DeathTrendu Decreasing) = (20+24 +1+22) = 67/90 = 0 - P(DeathTrend U Same) (20 + 24 +1+ 0) = 45/90 = 0.500

College Algebra
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section: Chapter Questions
Problem 2P: Family Planning A intend to have two children. What is tie probability that they will have child of...
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Answer this question using the contingency Table and probailities. 

Varaible 1 is Death trend 

Vraiable 2 is AdultVacTrend

AutoSave O ff ProveitPortfolio_Part1-1 (1) - Saved to this PC - Search Ejaz Irfan EI File Design Layout References Mailings Review View Help A Share P Comments Home Insert Draw X Cut - A A" Aa v Ao O Find - Times New Roma v 12 AaBbCcI AaBbCcDd AaBbCcI AaBbC AABBCCD AaBbCcDc AaBbCcD AaBbCcD AaB AABBCCC AaBbCcD B Copy & Replace Paste I Style1 Dictate Sensitivity Editor Reuse S Format Painter BIU - ab- х, A - I v A - 1 Normal I No Spac. Heading 1 Heading 2 Heading 3 Heading 4 Heading 5 Title Subtitle Subtle Em.. A Select v Files Clipboard Font Paragraph Styles Editing Voice Sensitivity Editor Reuse Files P(DeathTrend n Decreasing ) = 24/90 = 0.267 P((DeathTrend n Same) = 1/90 = 0.0111 DeathTrend AdultVacTrend ТОTAL P((AdultVacTrendo Increasing) = 23/90 = 0.256 P((AdultVacTrend n Decreasing ) = 22 / 90 = 0.244 inc 20 23 43 P((AdultVacTrendn Same) = 0/90 = 0 P(DeathTrend | Increasing) = 20/ 43 = 0.465 - P(DeathTrend | Decreasing ) = 24/ 46 = 0.522 dec 24 22 46 P(DeathTrend | Same ) = 1/1 = 1 P(AdultVacTrend | Increasing) = 23 / 43 = 0.535 1 1 • P(AdultvacTrend | Decreasing) = 22 / 46 = 0.478 sam • P(AdultVacTrend Same ) = 0/1 = 0 P(Increasing | DeathTrend) = 20/45 = 0.444 ТОTAL 45 45 90 • P(Decreasing| DeathTrend) = 24 / 45 = 0.533 - P(Same| DeathTrend) = 1/45 = 0.0222 Probabilities P(Increasing | AdultVacTrend) = 23 / 45 = 0.511 P(Decreasing | AdultVacTrend) = 22/ 45 = 0.489 P(Same | AdultVacTrend) = 0/45 = 0 - P(DeathTrend) = 45 / 90 = 0.500 P(AdultVacTrend) = 45/ 90 = 0.500 P(Increasing) = 43/ 90 = 0.478 P(Decreasing ) = 46 / 90 = 0.511 P(Same) = 1/90 = 0.0111 P(DeathTrend u Increasing) = (20 + 22 + 24 + 1) = 68 / 90 = 0.756 P(DeathTrend U Decreasing ) = (20 + 24 +1 +22) = 67/90 = 0.744 P(DeathTrend u Same ) = (20 + 24 +1+ 0) = 45 / 90 = 0.500 P(AdultVacTrend u Increasing) = (20 + 23 + 22 + 0) = 65 / 90 = 0.722 P(AdultVacTrend U Decreasing ) = (23 + 24 + 22 + 0) = 69/ 90 = 0.767 P(AdultvacTrend u Same ) = (23 + 22 +0+ 1) = 46/ 90 = 0.511 P(DeathTrendn Increasing) = 20/90 = 0.222 Page 19 of 23 D Focus 3626 words 86% 9:42 AM 7/30/2021 1 | « | > | 1>
Transcribed Image Text:AutoSave O ff ProveitPortfolio_Part1-1 (1) - Saved to this PC - Search Ejaz Irfan EI File Design Layout References Mailings Review View Help A Share P Comments Home Insert Draw X Cut - A A" Aa v Ao O Find - Times New Roma v 12 AaBbCcI AaBbCcDd AaBbCcI AaBbC AABBCCD AaBbCcDc AaBbCcD AaBbCcD AaB AABBCCC AaBbCcD B Copy & Replace Paste I Style1 Dictate Sensitivity Editor Reuse S Format Painter BIU - ab- х, A - I v A - 1 Normal I No Spac. Heading 1 Heading 2 Heading 3 Heading 4 Heading 5 Title Subtitle Subtle Em.. A Select v Files Clipboard Font Paragraph Styles Editing Voice Sensitivity Editor Reuse Files P(DeathTrend n Decreasing ) = 24/90 = 0.267 P((DeathTrend n Same) = 1/90 = 0.0111 DeathTrend AdultVacTrend ТОTAL P((AdultVacTrendo Increasing) = 23/90 = 0.256 P((AdultVacTrend n Decreasing ) = 22 / 90 = 0.244 inc 20 23 43 P((AdultVacTrendn Same) = 0/90 = 0 P(DeathTrend | Increasing) = 20/ 43 = 0.465 - P(DeathTrend | Decreasing ) = 24/ 46 = 0.522 dec 24 22 46 P(DeathTrend | Same ) = 1/1 = 1 P(AdultVacTrend | Increasing) = 23 / 43 = 0.535 1 1 • P(AdultvacTrend | Decreasing) = 22 / 46 = 0.478 sam • P(AdultVacTrend Same ) = 0/1 = 0 P(Increasing | DeathTrend) = 20/45 = 0.444 ТОTAL 45 45 90 • P(Decreasing| DeathTrend) = 24 / 45 = 0.533 - P(Same| DeathTrend) = 1/45 = 0.0222 Probabilities P(Increasing | AdultVacTrend) = 23 / 45 = 0.511 P(Decreasing | AdultVacTrend) = 22/ 45 = 0.489 P(Same | AdultVacTrend) = 0/45 = 0 - P(DeathTrend) = 45 / 90 = 0.500 P(AdultVacTrend) = 45/ 90 = 0.500 P(Increasing) = 43/ 90 = 0.478 P(Decreasing ) = 46 / 90 = 0.511 P(Same) = 1/90 = 0.0111 P(DeathTrend u Increasing) = (20 + 22 + 24 + 1) = 68 / 90 = 0.756 P(DeathTrend U Decreasing ) = (20 + 24 +1 +22) = 67/90 = 0.744 P(DeathTrend u Same ) = (20 + 24 +1+ 0) = 45 / 90 = 0.500 P(AdultVacTrend u Increasing) = (20 + 23 + 22 + 0) = 65 / 90 = 0.722 P(AdultVacTrend U Decreasing ) = (23 + 24 + 22 + 0) = 69/ 90 = 0.767 P(AdultvacTrend u Same ) = (23 + 22 +0+ 1) = 46/ 90 = 0.511 P(DeathTrendn Increasing) = 20/90 = 0.222 Page 19 of 23 D Focus 3626 words 86% 9:42 AM 7/30/2021 1 | « | > | 1>
Approximating Binomial Probabilities Use the table above to determine the probability of the increasing response rates in the variable 1 sample data set happening by accident. To do this you'll need to find the binomial approximation of the probability that a sample of 45 days will have a probability that falls below the value you got in your contingency table assuming there's a 50% chance of a day not falling in the increasing group (inc) for variable 1. p= q=. approximated x value = X= O = /npq=. H = np = b (x<. Use the table above to determine the probability of the increasing response rates in the variable 2 sample data set happening by accident. To do this you'll need to find the binomial approximation of the probability that a sample of 45 days will have a probability that falls below the value you got in your contingency table assuming there's a 50% chance of a day not falling in the increasing group (inc) for variable 2. p=. approximated x value = n = q= X= H = np = b (x< O = Jnpq=.
Transcribed Image Text:Approximating Binomial Probabilities Use the table above to determine the probability of the increasing response rates in the variable 1 sample data set happening by accident. To do this you'll need to find the binomial approximation of the probability that a sample of 45 days will have a probability that falls below the value you got in your contingency table assuming there's a 50% chance of a day not falling in the increasing group (inc) for variable 1. p= q=. approximated x value = X= O = /npq=. H = np = b (x<. Use the table above to determine the probability of the increasing response rates in the variable 2 sample data set happening by accident. To do this you'll need to find the binomial approximation of the probability that a sample of 45 days will have a probability that falls below the value you got in your contingency table assuming there's a 50% chance of a day not falling in the increasing group (inc) for variable 2. p=. approximated x value = n = q= X= H = np = b (x< O = Jnpq=.
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