Pencil Problem #74 7. Use the graph of ƒ(x)=x' to graph h(x)=(x- 3y° - 2.

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Chapter5: Solving Systems Of Linear Equations
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Objective #7: Graph functions involving a sequence of transformations. (pp.238-240)
A function involving more than one transformation can be graphed by performing transformations in the
recalculus 6e
following order:
Transformations
Eunction
Draw the grapnh of f and:
Horizontal
Translations
1
y = f(x– h)
Shift f to the right h units.
y = f(x+ h)
Shift f to the left h units.
2
Horizontal
y = f(bx); b >1
Horizontally shrink ƒ by dividing each of it x-coordinates by b.
Stretching or
Shrinking
y = f(bx); 0 < b< 1
Horizontally stretch ƒ by dividing each of it x-coordinates by b.
Vertical
Stretching or
Shrinking
y = af(x); a >1
Vertically stretch ƒ by multiplying each of it y-coordinates by a.
y = af(x); 0 < a<1
Vertically shrink ƒ by multiplying each of it y-coordinates by a.
3
Reflect f about the x-axis by changing the signs of y.
Reflections
y = -f(x)
y = f(-x)
Reflect f about the y-axis by changing the signs of x.
4
Shift f upward k units.
Vertical
Translations
y = f(x) + k
y = f(x) – k
Shift f downward k units.
*To calculate the actual horizontal translation when given af (bx -h) + k, set ḥx – h = 0 and solve.
Solved Problem #7
Pencil Problem #7
7. Use the graph of f(x)=x³ to graph
7. Use the graph of f(x)=x² to graph
g(x)=2(x- 1)² +3.
h(x)= (x- 3° - 2.
The graph of g is the graph of fhorizontally shifted to
the right 1 unit, vertically stretched by a factor of 2, and
vertically shifted up 3 units. Beginning with a point on
the graph of f, add 1 to each x-coordinate, then multiply
each y-coordinate by 2, and finally add 3 to each
y-coordinate.
(-1, 1) → (0, 1) → (0, 2) → (0, 5)
(0, 0) → (1, 0) → (1, 0) → (1, 3)
(1, 1) → (2, 1) → (2, 2) → (2, 5)
(0, 5) (2, 5)
t(1, 3)+
g(x) = 2(x – 1)² + 3
88
Copyright © 2018 Pearson Education Inc.
Transcribed Image Text:Objective #7: Graph functions involving a sequence of transformations. (pp.238-240) A function involving more than one transformation can be graphed by performing transformations in the recalculus 6e following order: Transformations Eunction Draw the grapnh of f and: Horizontal Translations 1 y = f(x– h) Shift f to the right h units. y = f(x+ h) Shift f to the left h units. 2 Horizontal y = f(bx); b >1 Horizontally shrink ƒ by dividing each of it x-coordinates by b. Stretching or Shrinking y = f(bx); 0 < b< 1 Horizontally stretch ƒ by dividing each of it x-coordinates by b. Vertical Stretching or Shrinking y = af(x); a >1 Vertically stretch ƒ by multiplying each of it y-coordinates by a. y = af(x); 0 < a<1 Vertically shrink ƒ by multiplying each of it y-coordinates by a. 3 Reflect f about the x-axis by changing the signs of y. Reflections y = -f(x) y = f(-x) Reflect f about the y-axis by changing the signs of x. 4 Shift f upward k units. Vertical Translations y = f(x) + k y = f(x) – k Shift f downward k units. *To calculate the actual horizontal translation when given af (bx -h) + k, set ḥx – h = 0 and solve. Solved Problem #7 Pencil Problem #7 7. Use the graph of f(x)=x³ to graph 7. Use the graph of f(x)=x² to graph g(x)=2(x- 1)² +3. h(x)= (x- 3° - 2. The graph of g is the graph of fhorizontally shifted to the right 1 unit, vertically stretched by a factor of 2, and vertically shifted up 3 units. Beginning with a point on the graph of f, add 1 to each x-coordinate, then multiply each y-coordinate by 2, and finally add 3 to each y-coordinate. (-1, 1) → (0, 1) → (0, 2) → (0, 5) (0, 0) → (1, 0) → (1, 0) → (1, 3) (1, 1) → (2, 1) → (2, 2) → (2, 5) (0, 5) (2, 5) t(1, 3)+ g(x) = 2(x – 1)² + 3 88 Copyright © 2018 Pearson Education Inc.
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