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Peter called to a an insurance company and was told that there was one customer ahead of him waiting for starting to be served. Suppose that at each moment, the time remaining for the next service does not depend on when the last service has begun, and the mean service time is 5 minutes. Answer Question 14-15 below. Write an integral that gives the probability that Peter will wait more than 9 min. 02/5, e-x/5 dx So x² e-5x dx 25 05e-2/5dx O 5 ]° xe-z/5da Oxe-x/5dx 25 J9

Peter called to a an insurance company and was told that there was one customer ahead of him waiting for starting to be served. Suppose that at each moment, the time remaining for the next service does not depend on when the last service has begun, and the mean service time is 5 minutes. Answer Question 14-15 below. Write an integral that gives the probability that Peter will wait more than 9 min. 02/5, e-x/5 dx So x² e-5x dx 25 05e-2/5dx O 5 ]° xe-z/5da Oxe-x/5dx 25 J9

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 54E
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Peter called to a an insurance company and was told that there was one customer ahead of him waiting for starting to be served. Suppose that at each moment, the time remaining for the next service does not depend on when the last service has begun, and the mean service time is 5 minutes. Answer Question 14-15 below. Write an integral that gives the probability that Peter will wait more than 9 min. 5,⁹ -x/5 e dx 1 Of x² e-5 dx 25 5e-2/5dx 5 xe 27/15 6,00⁰0 -x/5 dx xe -x/5 dx
Transcribed Image Text:Peter called to a an insurance company and was told that there was one customer ahead of him waiting for starting to be served. Suppose that at each moment, the time remaining for the next service does not depend on when the last service has begun, and the mean service time is 5 minutes. Answer Question 14-15 below. Write an integral that gives the probability that Peter will wait more than 9 min. 5,⁹ -x/5 e dx 1 Of x² e-5 dx 25 5e-2/5dx 5 xe 27/15 6,00⁰0 -x/5 dx xe -x/5 dx
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