petween a tie bar and concrete is 2 MPa, and the joint gap between the slabs is 10 mm. Ignoring the loss of bond and the colerance factor, the design length of the
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A: Lower Limit Asα = π0.54 = 0.1963 in2 Qn=0.5Asafc'Ec ≤ RgRpAsaFu =0.50.196343492 = 11.60 kips
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- A copper strip (Ec= 105 GPa) and an aluminum strip (Ea = 75 GPa) are bonded together to form the composite beam shown. Knowing that the beam is bent about a horizontal axis by a couple of moment M = 32 N-m, determine the maximum stress in the aluminum strip and in the copper strip. Aluminum Copper 24 mm 6 mm 6 mm The maximum compressive stress in the aluminum strip is -51.22 MPa (include a negative sign). The maximum tensile stress in the copper strip is 60.67 MPa.Tie bars of 12 mm diameter are to be provided in a concrete pavement slab. The working tensile stress of the tie bars is 230 MPa, the average bond strength between a tie bar and concrete is 2 MPa, and the joint gap between the slab is 10mm. Ignoring the loss of bond and the tolerance factor, the design length of the tie bars (in mm, round off to the nearest integer) is1. A specimen of steel 20 mm diameter with a gauge length of 200 n.m is tested io destruction. It' has an extension of 0.25 mm under a load of 80 kN and the load at elasti limit is 102 kN The maximum load is 130 kN. The total extension at fracture is 56 mm and diameter at neck is 15 mm. Find (i) The stress at elastic limit. (ii) Young's modulus. (iii) Percentage elongation. (iv) Percentage reduction in area. (v) Ultimate tensile stress
- The state of plane stress shown occurs at a critical point of a steel machine component. As a result of several tensile tests, it has been found that the tensile yield strength is o, = 250 MPa for the grade of steel used. Determine the factor of safety with respect to yield using (a) the maximum shearing stress criterion, and (b) the maximum distortion energy criterion. ↑y 40 40 MPa 80 MPa 25 MPa ➜X7) A specimen of steel 20 mm diameter with a gauge length of 200 mm is tested to destruction. It has an extension of 0.25 mm under a load of 80 kN and the load at elastic limit is 102 kN. The maximum load is 130 kN. The total extension at fracture is 56 mm and diameter at neck is 15 mm. Find (i) The stress at elastic limit. (ii) Young's modulus. (iii) Percentage elongation. (iv) Percentage reduction in area. (v) Ultimate tensile stress.1. A specimen of steel 20 mm diameter with a gauge length of 200 n.m is tested io destruction. It' has an extension of 0.25 mm under a load of 80 kN and the load at elastic limit is 102 kN The maximum load is 130 kN. The total extension at fracture is 56 mm and diameter at neck is 15 mm. Find (i) The stress at elastic limit. (ii) Young's modulus. (iii) Percentage elongation. (iv) Percentage reduction in area. (v) Ultimate tensile stress
- A copper strip (Ec= 105 GPa) and an aluminum strip (Ea = 75 GPa) are bonded together to form the composite beam shown. Knowing that the beam is bent about a horizontal axis by a couple of moment M= 33 N-m, determine the maximum stress in the aluminum strip and in the copper strip. Aluminum Copper 24 mm 6 mm 6 mm The maximum compressive stress in the aluminum strip is The maximum tensile stress in the copper strip is MPa. MPa (include a negative sign).3. A steel specimen is tested in tension. The specimen is 1.0 in. wide by 0.25 in. thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 12.5 kips and fractured at 17.5 kips. а. Determine the tensile stresses at yield and at fracture. b. Estimate how much increase in length would occur at 60% of the yield stress in a 2-in. gauge lengthAn aluminum pipe must not stretch more than 0.05in when it issubjected to a tensile load. Knowing that E=10.1x10^6psi and that the maximum allowable normal stress is 14ksi, determine (a) the maximum allowable length of the pipe, and (b) the required area of the pipe if the tensile load is 127.5kips.
- The state of two dimensional stress acting on a concrete lamina consists of a direct tensile stress of 6 MPa and shear stress of 4 MPa, which cause cracking of concrete. Then the tensile strength of the concrete in MPa isA 1 foot plate with a 0.25-inch thickness has a width of 2.4 inch and a hole at the middle with a diameter of 2 inch. The material has an ultimate strength of 132 ksi and a yield strength of 84 ksi. A repeated 52N tensile load is applied along its neutral axis in the direction of its length at a temperature of 90 degree fahrenheit. The surface finish is Ground. The reliability of the material is targeted at 99.99%. Calculate: The Theoretical Stress Concentration Factor The Fatigue Stress Concentration Factor The Factor of Safety for the Goodman Criterion The Factor of Safety for the Soderberg Criterion The Factor of Safety for the Gerber Criterion The Factor of Safety for the ASME-Elliptic Criterion.> * The state of two-dimensional stresses acting on a concrete lamina consists of a direct tensile stress o. = 1.5 N/mm² and shear stress T = 1.20 N/mm², when cracking of concrete is just impending. The permissible tensile strength of the concrete is