A Gaussian surface with rectangular size has a positive point charge +q at its center, as shown in the figure below. If the amount of charge inside doubles while the Gaussian surface shrinks to half of its original surface area, the electric flux through the surface of this Gaussian box will O decrease by 1/2. O increase by a factor of 4. O increase by a factor of 2. O decrease by 1/4. O None of the given choices

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Author:Raymond A. Serway, John W. Jewett
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Chapter24: Gauss’s Law
Section: Chapter Questions
Problem 24.10OQ: A cubical gaussian surface is bisected by a large sheet of charge, parallel to its top and bottom...
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A Gaussian surface with rectangular size has a positive point charge +q at its center, as shown in
the figure below. If the amount of charge inside doubles while the Gaussian surface shrinks to half
of its original surface area, the electric flux through the surface of this Gaussian box will
O decrease by 1/2.
O increase by a factor of 4.
O increase by a factor of 2.
O decrease by 1/4.
O None of the given choices
Transcribed Image Text:A Gaussian surface with rectangular size has a positive point charge +q at its center, as shown in the figure below. If the amount of charge inside doubles while the Gaussian surface shrinks to half of its original surface area, the electric flux through the surface of this Gaussian box will O decrease by 1/2. O increase by a factor of 4. O increase by a factor of 2. O decrease by 1/4. O None of the given choices
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