Pink eye and albinism are two recessive traits found in the deer mouse, Peromyscus maniculatus. In mice with pink eye, the eye is devoid of color and appears pink from the blood vessels within it. Albino mice are completely lacking color both in their fur and in their eyes. F. H. Clark crossed pink‑eyed mice with albino mice; the resulting F1 had normal coloration in their fur and eyes. He then crossed these F1 mice with mice that were pink‑eyed and albino and obtained the mice shown in the table below. It is very hard to distinguish between mice that are albino and mice that are both pink‑eyed and albino, so he combined these two phenotypic classes (F. H. Clark, 1936, Journal of Heredity 27:259−260).Match the expected numbers of progeny with each phenotype if the genes for pink‑eye and albinism assort independently.PhenotypeObservedExpectedwild type, wild type12 wild type, pink eyes62 albino, wild type, or pink eyes78 Total152152  Answer Bank38761521140 Use a chi‑square test to determine if the observed numbers of progeny fit the number expected with independent assortment.χ2=  Does this chi‑square value fit the number expected with independent assortment?YesNo

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Asked Sep 14, 2019
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Pink eye and albinism are two recessive traits found in the deer mouse, Peromyscus maniculatus. In mice with pink eye, the eye is devoid of color and appears pink from the blood vessels within it. Albino mice are completely lacking color both in their fur and in their eyes. F. H. Clark crossed pink‑eyed mice with albino mice; the resulting F1 had normal coloration in their fur and eyes. He then crossed these F1 mice with mice that were pink‑eyed and albino and obtained the mice shown in the table below. It is very hard to distinguish between mice that are albino and mice that are both pink‑eyed and albino, so he combined these two phenotypic classes (F. H. Clark, 1936, Journal of Heredity 27:259−260).

Match the expected numbers of progeny with each phenotype if the genes for pink‑eye and albinism assort independently.

Phenotype Observed Expected
wild type, wild type 12  
wild type, pink eyes 62  
albino, wild type, or pink eyes 78  
Total 152 152
 
 
Answer Bank
38
76
152
114
0
 
Use a chi‑square test to determine if the observed numbers of progeny fit the number expected with independent assortment.
χ2=
 
 
Does this chi‑square value fit the number expected with independent assortment?
Yes
No
check_circle

Expert Answer

Step 1

In this case, albinism and pink eye color are recessive traits found within the deer mouse Peromyscus maniculatus. So, the wild type fur color is expressed by gene A where a corresponds to the recessive allele.

P corresponds to dominant wild type eye color allele and p corresponds to the recessive allele.

 

At first, F. H. Clarke crossed albino mice with pink-eyed mice and the F1 (first filial) generation showed normal coloration in fur and eyes.

 

Parental – ppaa X PPAA

F1 generation – PpAa (wild type fur and wild type eye color)

 

Again, the F1 offspring were crossed to pink-eyed, albino mice, so the cross is between PpAa and ppaa.

 

Step 2

The four genotypic combinations produced in F2 generation will be PpAa (wild type eye color and wild type fur), Ppaa (wild type eye color and albino), ppAa (pink eyed wild type fur) and ppaa (pink eyed albino).

 

Following independent assortment of Mendel, phenotypic ratio for a dihybrid cross is 1:2:1.

Hence, expected frequencies for homozygous dominant individuals among the overall population = ¼

Expected frequencies for heterozygous individuals among total population = ½

Expected frequencies for homozygous recessive individuals among total population = ¼

 

Here, total mice in population is given as 152.

 

Therefore, wild type fur and wild type eye colored mice = ¼ X 152 = 38.

 

Expected frequency of wild type, pink eyes mice = ¼ X 152 = 38.

 

Expected frequency of albino, wild type or pink eyes = ½ X 152 = 76

Step 3

 

Observed (O)

Expected (E)

(O-E)2

(O-E)2/E

Wild type, wild type

12

38

676

17.78

Wild type, pink eyes

62

38

576

15.15

albino, wild type, or pink eyes

78

76

4

0.052

Total

152

152

 

32.982

 

 

So, the chi-square value is 32.982 that is almost equal to 33.

 

There are four alleles involved in this case and hence, the degrees of freedom will be (4-1) = 3.

...

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