Pl anet # 1 M3 M1 ..... .... Planet # 2 Planet # 3 Planet #2 (mass M2) and planet #3 (mass M3) are separated by distance R. Planet #1 of mass M, is directly between these two planets. What is the force F12 on planet #1 due to the gravitational force of planet #2 at the position r in the above figure? O F12 = GM,M2 / 3 O F12 = GM1 / r? O F12 = GM1M2/r O F12 = GM1M2 /? O F12 = GM,M2r? %3D %3D !3! %3D %3D Submit Answer Tries 0/2 What is the direction of the force F12? toward planet 1 perpendicular to the line joining planet 1 and planet 2 toward planet 3 toward planet 2 Submit Answer Tries 0/2 What is the force F13 on planet #1 due to the gravitational force of planet #3 at the position r in the above figure? F13 = GM1M3 / R? %3D F13 = GM1M3(R-r)² F13 = GM1M3/ (R-r) %3D %3D F13 = GM1M3/ r2 F13 = GM1M3 / (R-r)2 Submit Answer Tries 0/2 What is the direction of the force F13? toward planet 2 toward planet 1 perpendicular to the line joining planet 1 and planet 3 O toward planet 3

Glencoe Physics: Principles and Problems, Student Edition
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ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter7: Gravitation
Section: Chapter Questions
Problem 5STP
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Planet # 1
M3
M1
M2
Planet # 2
Planet # 3
Planet #2 (mass M2) and planet #3 (mass M3) are separated by distance R. Planet #1 of mass M, is
directly between these two planets.
What is the force F12 on planet #1 due to the gravitational force of planet #2 at the positionr in the
above figure?
O F12 = GM,M2 /13
O F12 = GM1 / r2
F12 = GM1M2 / r
%3D
%3D
F12 = GM1M2 / 2
O F12 = GM1M2r?
%3D
%3D
Submit Answer
Tries 0/2
What is the direction of the force F12?
toward planet 1
perpendicular to the line joining planet 1 and planet 2
toward planet 3
toward planet 2
Submit Answer
Tries 0/2
What is the force F13 on planet #1 due to the gravitational force of planet #3 at the position r in the
above figure?
F13 = GM1M3/ R2
%3D
F13 = GM1M3(R-r)2
F13 = GM1M3/ (R-r)
%3D
%3D
F13 = GM1M3/ r2
%3D
F13 = GM1M3/ (R-r)2
%3D
Submit Answer
Tries 0/2
What is the direction of the force F13?
toward planet 2
toward planet 1
perpendicular to the line joining planet 1 and planet 3
toward planet 3
Transcribed Image Text:Planet # 1 M3 M1 M2 Planet # 2 Planet # 3 Planet #2 (mass M2) and planet #3 (mass M3) are separated by distance R. Planet #1 of mass M, is directly between these two planets. What is the force F12 on planet #1 due to the gravitational force of planet #2 at the positionr in the above figure? O F12 = GM,M2 /13 O F12 = GM1 / r2 F12 = GM1M2 / r %3D %3D F12 = GM1M2 / 2 O F12 = GM1M2r? %3D %3D Submit Answer Tries 0/2 What is the direction of the force F12? toward planet 1 perpendicular to the line joining planet 1 and planet 2 toward planet 3 toward planet 2 Submit Answer Tries 0/2 What is the force F13 on planet #1 due to the gravitational force of planet #3 at the position r in the above figure? F13 = GM1M3/ R2 %3D F13 = GM1M3(R-r)2 F13 = GM1M3/ (R-r) %3D %3D F13 = GM1M3/ r2 %3D F13 = GM1M3/ (R-r)2 %3D Submit Answer Tries 0/2 What is the direction of the force F13? toward planet 2 toward planet 1 perpendicular to the line joining planet 1 and planet 3 toward planet 3
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