Please answer asap 1(b). The integral of the p.d.f. as displayed over the support is 2; the x-axis should be scaled down by 1/2 (so the vertex should (1,3/4) instead of (1,3/2) as displayed). Thank You
Please answer asap 1(b). The integral of the p.d.f. as displayed over the support is 2; the x-axis should be scaled down by 1/2 (so the vertex should (1,3/4) instead of (1,3/2) as displayed). Thank You
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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q1
Please answer asap
1(b). The integral of the
Thank You
![Problem 1. Continuous Distributions. For the following, provide a random variable from
the formula sheet and (possibly) a transformation of that variable that produces a distribution
satisfying the given constraints. For example, your answer could look something like
the random variable X = g(Z)
where Z~ {distribution from sheet} and g(x) = {some function}.
a) Find a distribution that satisfies the following:
Supp(X) = {x:x>0}
E[X] = 3
V[X] = 5.
b) The distribution of X has a p.d.f. given by the following parabola:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fef0ec5e6-9fc1-4070-9f90-1c13b545c4e3%2Ffd39ffb8-2452-4772-99bf-1035ed1645f2%2Foubqxuo_processed.png&w=3840&q=75)
Transcribed Image Text:Problem 1. Continuous Distributions. For the following, provide a random variable from
the formula sheet and (possibly) a transformation of that variable that produces a distribution
satisfying the given constraints. For example, your answer could look something like
the random variable X = g(Z)
where Z~ {distribution from sheet} and g(x) = {some function}.
a) Find a distribution that satisfies the following:
Supp(X) = {x:x>0}
E[X] = 3
V[X] = 5.
b) The distribution of X has a p.d.f. given by the following parabola:
![on support
p.d.f.
3/2-
1-
1/2-
0-
1/2
Supp(X) = {x : x = [0, 2]}.
c) The distribution of X has the following p.d.f.:
Supp(X) = {x : x > 0}
1
fx(x)
=
2πT
3/2
xe
2V27.
2V2T
-~
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fef0ec5e6-9fc1-4070-9f90-1c13b545c4e3%2Ffd39ffb8-2452-4772-99bf-1035ed1645f2%2Fv2llop_processed.png&w=3840&q=75)
Transcribed Image Text:on support
p.d.f.
3/2-
1-
1/2-
0-
1/2
Supp(X) = {x : x = [0, 2]}.
c) The distribution of X has the following p.d.f.:
Supp(X) = {x : x > 0}
1
fx(x)
=
2πT
3/2
xe
2V27.
2V2T
-~
2
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