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PLEASE EXPLAIN THE PHOTO

PLEASE EXPLAIN THE PHOTO

Chemistry In Focus
Chemistry In Focus
7th Edition
ISBN:9781337399692
Author:Tro, Nivaldo J.
Publisher:Tro, Nivaldo J.
Chapter14: Oxidation And Reduction
Section: Chapter Questions
Problem 3SC: Closely examine Figure 14.1 and explain why no reaction occurs in part d. Because copper ions have a...
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PLEASE EXPLAIN THE PHOTO

• The normal charge of an ion can be quickly determined using the oxidation number of an element. - The oxidation number of an atom is the charge that atom would have if the compound was composed of ions. To find the oxidation number : +1 -1 0 +4 +3 -4 -3 -2 VIA VIILA H He O Look at Group # I Determine # of valence electrons O If 4 or less, atom will lose (give away) valence electrons (ion is positive) IA +2 H IIA IIIA IVA VA VIA 6 BCN 3 4 10 Li Be F Ne 11 12 13 14 IS 16 17 18 Na Mg Al Si P ciAr 19 20 21 22 29 30 31 32 33 34 35 36 K Ca Sc | Ti Cu Zn Ga Ge As Se Br Kr 31 32 53 Ag Cd In Sn Sb Te 37 38 39 40 47 48 49 50 54 Rb Sr Y|Zr I Xe O If 4 or more, atom will gain the needed # to fill valence shell. (ion is negative) 55 56 57 72 80 8T Au Hg| TI Pb Bi Po At Rn 79 82 83 84 85 Cs Ba La Hf 87 89 104 112 114 116 118 Fr Ra Ac Rf
Transcribed Image Text:• The normal charge of an ion can be quickly determined using the oxidation number of an element. - The oxidation number of an atom is the charge that atom would have if the compound was composed of ions. To find the oxidation number : +1 -1 0 +4 +3 -4 -3 -2 VIA VIILA H He O Look at Group # I Determine # of valence electrons O If 4 or less, atom will lose (give away) valence electrons (ion is positive) IA +2 H IIA IIIA IVA VA VIA 6 BCN 3 4 10 Li Be F Ne 11 12 13 14 IS 16 17 18 Na Mg Al Si P ciAr 19 20 21 22 29 30 31 32 33 34 35 36 K Ca Sc | Ti Cu Zn Ga Ge As Se Br Kr 31 32 53 Ag Cd In Sn Sb Te 37 38 39 40 47 48 49 50 54 Rb Sr Y|Zr I Xe O If 4 or more, atom will gain the needed # to fill valence shell. (ion is negative) 55 56 57 72 80 8T Au Hg| TI Pb Bi Po At Rn 79 82 83 84 85 Cs Ba La Hf 87 89 104 112 114 116 118 Fr Ra Ac Rf
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