Please explain why square root of two is multiplited to the force of P in the following solution AE9DDBFGBDETAL42xA cube of side a is acted upon by a force P as shown. Determine themoment of P (a) about A. (b) about the edge AB, (e) about the diagonalAG of the cube, (d). Using the result of part c, determine the perpendiculardistance between AG and FC.SOLUTIONa. Moment about A. Choosing x, y, and axes as shown, we resolve intorectangular components the force P and the vector rAAF drawn fromA to the point of application F of P.TEA = ai aja(i- j)P = (P/V2)j - (P/V2)k= (P/V2) (jk)The moment of P about A isMAFFIA X P = a(i-j) × (P/V2) (j - k)M₁ = (aP/V2) (i+j+k)

The force P acts on the square plane BCGF, along the diagonal FC. It has components in the Y and Z…

Answered: Please explain why square root of two…

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Please explain why square root of two is multiplited to the force of P in the following solution

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter11: Angular Momentum

Section: Chapter Questions

Problem 37P: A particle of mass 5.0 kg has position vector at a particular instant of time when its velocity is...

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Question

Please explain why square root of two is multiplited to the force of P in the following solution

A
E
9
D
D
B
F
G
B
DETAL
42
x
A cube of side a is acted upon by a force P as shown. Determine the
moment of P (a) about A. (b) about the edge AB, (e) about the diagonal
AG of the cube, (d). Using the result of part c, determine the perpendicular
distance between AG and FC.
SOLUTION
a. Moment about A. Choosing x, y, and axes as shown, we resolve into
rectangular components the force P and the vector rAAF drawn from
A to the point of application F of P.
TEA = ai aja(i- j)
P = (P/V2)j - (P/V2)k= (P/V2) (jk)
The moment of P about A is
MAFFIA X P = a(i-j) × (P/V2) (j - k)
M₁ = (aP/V2) (i+j+k)

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