Please help me answer how much volume of cell suspension needed (for 5*10^4 cells) in microliters. Pertinent Information shown in the image

Basic Clinical Laboratory Techniques 6E
6th Edition
ISBN:9781133893943
Author:ESTRIDGE
Publisher:ESTRIDGE
Chapter2: Basic Hematology
Section2.4: The Hemacytometer
Problem 9RQ
icon
Related questions
Question
100%

Please help me answer how much volume of cell suspension needed (for 5*10^4 cells) in microliters. Pertinent Information shown in the image. 

Determine the number of cells you have per ml of your cell suspension.
Number of cells counted in quadrant 1 =
46
Number of cells counted in quadrant 2 =
38
Number of cells counted in quadrant 3 =
56
Number of cells counted in quadrant 4 =
38
TOTAL number of cells for ALL 4 quadrants =
178
Number of cells per ml will equal:
[(total # of cells counted) divided by 4] X 104 =,
scientific notation)
_445,000_
cells/ml (use
B. Setting up a new culture of cells
1. You will need to determine the volume of your cell suspension needed to obtain 5 x 10^4 cells.
Use the value for cells per ml you determined above in Part A.
Example: If your cells per ml = 2 x 105
5 x 104 cells
= 0.25 ml, or 250 ul suspension
2 x 105 cells/ml
5 x 10^4 cells
0.12235955
= Volume of cell suspension needed:
mL
cells/mL
Volume of cell suspension needed (for 5 x 104 cells):
_microliters (uL)
These cells will be used to prepare "protein lysate" for western blot.
Transcribed Image Text:Determine the number of cells you have per ml of your cell suspension. Number of cells counted in quadrant 1 = 46 Number of cells counted in quadrant 2 = 38 Number of cells counted in quadrant 3 = 56 Number of cells counted in quadrant 4 = 38 TOTAL number of cells for ALL 4 quadrants = 178 Number of cells per ml will equal: [(total # of cells counted) divided by 4] X 104 =, scientific notation) _445,000_ cells/ml (use B. Setting up a new culture of cells 1. You will need to determine the volume of your cell suspension needed to obtain 5 x 10^4 cells. Use the value for cells per ml you determined above in Part A. Example: If your cells per ml = 2 x 105 5 x 104 cells = 0.25 ml, or 250 ul suspension 2 x 105 cells/ml 5 x 10^4 cells 0.12235955 = Volume of cell suspension needed: mL cells/mL Volume of cell suspension needed (for 5 x 104 cells): _microliters (uL) These cells will be used to prepare "protein lysate" for western blot.
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Nutrient growth medium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Basic Clinical Laboratory Techniques 6E
Basic Clinical Laboratory Techniques 6E
Biology
ISBN:
9781133893943
Author:
ESTRIDGE
Publisher:
Cengage
Biomedical Instrumentation Systems
Biomedical Instrumentation Systems
Chemistry
ISBN:
9781133478294
Author:
Chatterjee
Publisher:
Cengage