Please help me check if I completed these two question correctly. Please check if I have the correct answers and I have shown the correct steps

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter2: Functions And Graphs
Section2.2: The Rectangular Coordinate System And Graphing Lines
Problem 91E
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Please help me check if I completed these two question correctly. Please check if I have the correct answers and I have shown the correct steps 

 

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Image #2: My work 

1. If7-7-7+2k, y=37+7-7k and Z=37+k, simplify 2(-y)+Z?
2.
ABC is a triangle with vertices A (-2, 2, 3), B(2, 2, 5), and C(0, 0, 9). Determine AB x AC.
Transcribed Image Text:1. If7-7-7+2k, y=37+7-7k and Z=37+k, simplify 2(-y)+Z? 2. ABC is a triangle with vertices A (-2, 2, 3), B(2, 2, 5), and C(0, 0, 9). Determine AB x AC.
we need to find
11
11
NOW
AB
А
and AC
Therefore 212²-²) + Z
-чі -5 + 19 2
(2) ABC is
a
triangle with vertices A(-2,2,3)
B (2, 2, 5) and c(0,0,9). Determine ABXAZ
we need
to find AB X Ad
x
AB
B² - A
=
AC
ABX AC
2(x²-7²) +2²
((-³ + 2K) - (3i+5 − 7 7 ) ) + ( 3 5 + ² )
2 (-2₁ - 25+ (2R+7R)) +(35+ R)
2 (-21-25 + 9K²) + (3 5 + R)
(-45-45+ 18K²¹) + (3) + R²³)
-4-₁ + (-4+ 3) + (18+1)
-4 ₁² + (-1) 5 +
= −4j-j +19 R
(2√² + 2) + 5k) - (~2j+23+3R)
(2+2) i + (2-2); +(5-3) K²
=
yú tak
1
ÁP XÁC
=
2-A)
= (0₁+ oj +9R²) - (-2√² +2²3 +3K²)
(0+2) i + (0-2); + (9-3) ₁²
21-21 +6R
19 k
二
i
2
j
40
ช
K
2
6
=j (0-1-2) (2)) -3 | 4 (6) - 2/2)) + 1² (41-2)-0)
· 4i - i (24-4) + k^² (-8)
4₁-2018 1²
Transcribed Image Text:we need to find 11 11 NOW AB А and AC Therefore 212²-²) + Z -чі -5 + 19 2 (2) ABC is a triangle with vertices A(-2,2,3) B (2, 2, 5) and c(0,0,9). Determine ABXAZ we need to find AB X Ad x AB B² - A = AC ABX AC 2(x²-7²) +2² ((-³ + 2K) - (3i+5 − 7 7 ) ) + ( 3 5 + ² ) 2 (-2₁ - 25+ (2R+7R)) +(35+ R) 2 (-21-25 + 9K²) + (3 5 + R) (-45-45+ 18K²¹) + (3) + R²³) -4-₁ + (-4+ 3) + (18+1) -4 ₁² + (-1) 5 + = −4j-j +19 R (2√² + 2) + 5k) - (~2j+23+3R) (2+2) i + (2-2); +(5-3) K² = yú tak 1 ÁP XÁC = 2-A) = (0₁+ oj +9R²) - (-2√² +2²3 +3K²) (0+2) i + (0-2); + (9-3) ₁² 21-21 +6R 19 k 二 i 2 j 40 ช K 2 6 =j (0-1-2) (2)) -3 | 4 (6) - 2/2)) + 1² (41-2)-0) · 4i - i (24-4) + k^² (-8) 4₁-2018 1²
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