Please help me fill in the blanks Step 3Perform row operations to make the nonzero entry in the third row equal to 1.41.1 036710 16w/130 0414141Perform row operations to make the third entries in first and second rows equal to 0.10 0 :4828241TR3 + R1 -0 10:R3 + R24141416.130 0 1414141The matrix is now of the form- lo... Use an inverse matrix to solve (if possible) the system of linear equations.4x - 2y + 3z = 142x + 2y + 5z = 18Bx - 5y - 2z = 38Step 1Recall that if A is an invertible matrix, the system of linear equations represented by AX = B has a unique solution given byX = A-B. The system of equations is given below.4x - 2y + 3z = 142x + 2y + 5z = 188x - 5y - 2z = 38The system can be represented as a matrix equation AX = B where A is the coefficient matrix and B is the matrix of constantterms. In order to solve the system, you need to find A.Use elementary row operations on the doubly augmented matrixto row reduce A to 1. You can obtain the inverse fromthe resultant matrix4 -2 3 :1002 25:0 108 -5 -2 : 0 0 1]What is the coefficient matrix?3A =8.-5|-2[4,2,3;2,2,5;8,-5,-2]Step 2Perform row operations to make the first entries in the second and third rows equal to 0.4-20 0R + R227/27/2 1/2-1/21 03-20 1-2 R1 + R31.Perform row operations to make the first nonzero entries in the first and second rows equal to 1.131R.7TR2 --2Perform row operations to make the second entries in the first and third rows equal to 0.41 03R2 + R170 1R2 + Rg ---4113-41130 06.-10- |m - m

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Accepted Answer

Given:
The system of equation is:4x-2y+3z=142x+2y+5z=188x-5y-2z=38
To Find:
Represent the above…