please solve it in clearnote: The fifth section solved it by using MATLABi need all qusestion solved 1-9For the mass spring damper system shown in the figure, assume that m = 0.25 kg, k= 2500 N/m,and c = 10 N.s/m. The values of force measured at 0.05-second intervals in one cycle are givenbelow.0.050.100.150.200.250.300.350.40timeF(t)time12144419333412220.60250.450.500.550.650.700.750.800.85Force3211183049403521time0.900.95F(t)11m+xF(1)1- Find the equation of motion.2- Find the homogenous solution.3- If we excite the system with initial displacement and velocity as 5 mm and 0.2 m/srespectively, plot the response of the free vibration system.4- Use the generated plot in part 3 to verify the value of the damping constant, c.5- Find the steady state solution (only particular solution) for the forced vibration system.Take number of terms in your Fourier series terms from this range [ 30 – 55).6- Plot the force in the table, and the Fourier series expansion of the force (same graph).7- Plot the steady state solution.8- Find the total solution for the forced system with the initial conditions given in part 3.9- Plot the total solution found in part 8.

DAMPED SYSTEM or NON-MACHINE ANALYSIS Damping is any impact, either purposely induced or innate to a…

please solve it in clear note: The fifth section solved it by using MATLAB i need all qusestion solved 1-9 For the mass spring damper system shown in the figure, assume that m = 0.25 kg, k= 2500 N/m, and c = 10 N.s/m. The values of force measured at 0.05-second intervals in one cycle are given below. 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 time F(t) 12 14 44 19 33 34 12 22 time 0.45 0.50 0.55 0.60 0.65 0.70 0.75 0.80 0.85 Force 32 11 18 25 30 49 40 35 21 time 0.90 0.95 F(t) 11 m +x F(t) 1- Find the equation of motion. 2- Find the homogenous solution.

please solve it in clear note: The fifth section solved it by using MATLAB i need all qusestion solved 1-9 For the mass spring damper system shown in the figure, assume that m = 0.25 kg, k= 2500 N/m, and c = 10 N.s/m. The values of force measured at 0.05-second intervals in one cycle are given below. 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 time F(t) 12 14 44 19 33 34 12 22 time 0.45 0.50 0.55 0.60 0.65 0.70 0.75 0.80 0.85 Force 32 11 18 25 30 49 40 35 21 time 0.90 0.95 F(t) 11 m +x F(t) 1- Find the equation of motion. 2- Find the homogenous solution.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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