Please use the image below to answer these questions1. Considering the air resistance problem. What is the acceleration altitude of 2900ft? Show all work and be sure to include units(including directions)2. At which altitude (s) has the skydiver reached terminal velocity? How do you know?3. At 2900 feet, the skydiver is ——. Mark all that applya) moving upwardB) speeding upC) moving downward D) slowing down. A skydiver jumps out of a helicopter at6000 feet above the ground. As hedescends, the force of air resistance actingupon him continually changes. The free-body diagrams below represent themagnitude and direction of the two forcesacting upon the skydiver at six positionsduring his fall.MC6000 feetCRCFguv3000 feet-900 Nm/s/sFair=1100 Ngrav=900 Nm/s/sa=5500 feetFair 200 NFay=900 N2900 feetm/s/s a=Faiz-1500 N900 N4500 feetFair= 900 Nv-900 N1500 feetm/s/sFair-900 Ngav 900 Nm/s/s a=For each diagram (altitude) apply Newton'ssecond law (Fnet = m*a) to determine theacceleration value. Be sure to note thedirection of acceleration as well. (Hint: Todetermine the sky diver's mass, considerwhat you have learned about the linkbetween gravitational force and mass.)m/s/sYou may use 10 m/s/s as an approximationfor g (gravitational acceleration).

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University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter5: Newton's Law Of Motion

Section: Chapter Questions

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Please use the image below to answer these questions 1. Considering the air resistance problem. What is the acceleration altitude of 2900ft? Show all work and be sure to include units(including directions) 2. At which altitude (s) has the skydiver reached terminal velocity? How do you know? 3. At 2900 feet, the skydiver is ——. Mark all that apply a) moving upward B) speeding up C) moving downward D) slowing down.

A skydiver jumps out of a helicopter at
6000 feet above the ground. As he
descends, the force of air resistance acting
upon him continually changes. The free-
body diagrams below represent the
magnitude and direction of the two forces
acting upon the skydiver at six positions
during his fall.
MC
6000 feet
CR
C
Fguv
3000 feet
-900 N
m/s/s
Fair=1100 N
grav=900 N
m/s/s
a=
5500 feet
Fair 200 N
Fay=900 N
2900 feet
m/s/s a=
Faiz-1500 N
900 N
4500 feet
Fair= 900 N
v-900 N
1500 feet
m/s/s
Fair-900 N
gav 900 N
m/s/s a=
For each diagram (altitude) apply Newton's
second law (Fnet = m*a) to determine the
acceleration value. Be sure to note the
direction of acceleration as well. (Hint: To
determine the sky diver's mass, consider
what you have learned about the link
between gravitational force and mass.)
m/s/s
You may use 10 m/s/s as an approximation
for g (gravitational acceleration).

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