PLEASE, WRITE THE SOLUTIONS ON PAPER, EXPLAINING THE ENTIRE PROCESS, THE ONLY AND CORRECT ANSWERS ARE FOR (i) V(t) = exp (-2e^0.02t+ 2) for 0 < t <10, V(t) = exp(-0.0928 -0.03t- 0.0005t^2) for 10 < t <15, V(t) = exp ( 0.0197 - 0.045t) for 15 15 (i) Derive, and simplify as far as possible, expressions in terms of t for V(t), where V(t) is the present value of a unit sum of cash flow made at time t. You should derive separate expressions for the three sub-intervals. (ii) Hence, making use of the result in part (i), calculate the value at time t = 3 of a payment of £2,500 made at time t = 15. (iii) Calculate, to the nearest 0.01%, the constant nominal annual rate of interest convertible half-yearly implied by the transaction in part (ii). (iv) Making use of the result in part (i), calculate the present value of a payment stream p(t) paid continuously from time t = 15 to t = 20 at a rate of payment at time t given by: p(t) = 300e 0.02t

Essentials Of Investments
11th Edition
ISBN:9781260013924
Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.
Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.
Chapter1: Investments: Background And Issues
Section: Chapter Questions
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PLEASE, THE ONLY CORRECT ANSWERS ARE THE STIPULATED ONES, SOLVE IT USING FORMULAS NO TABLES

PLEASE, WRITE THE SOLUTIONS ON PAPER, EXPLAINING THE ENTIRE PROCESS, THE ONLY AND
CORRECT ANSWERS ARE FOR (i) V(t) = exp (-2e^0.02t+ 2) for 0 < t <10, V(t) = exp(-0.0928 -0.03t-
0.0005t^2) for 10 < t <15, V(t) = exp ( 0.0197 - 0.045t) for 15 <t.
AND (ii) C3 £2500 x 0.5877 = £1,469.16
AND (iii) i^2=4.48% pa
AND (iv) PV £988.38
The force of interest 8 (t) at any time t, measured in years, is given by:
0<t≤ 10
10t≤15
0.04e0.
0.02t
for
8(t) =
= 0.03 0.001t
for
0.045
for
t> 15
(i)
Derive, and simplify as far as possible, expressions in terms of t for V(t), where V(t) is
the present value of a unit sum of cash flow made at time t. You should derive separate
expressions for the three sub-intervals.
(ii)
Hence, making use of the result in part (i), calculate the value at time t = 3 of a payment of
£2,500 made at time t = 15.
(iii) Calculate, to the nearest 0.01%, the constant nominal annual rate of interest convertible
half-yearly implied by the transaction in part (ii).
(iv) Making use of the result in part (i), calculate the present value of a payment stream p(t)
paid continuously from time t = 15 to t = 20 at a rate of payment at time t given by:
p(t) = 300e 0.02t
Transcribed Image Text:PLEASE, WRITE THE SOLUTIONS ON PAPER, EXPLAINING THE ENTIRE PROCESS, THE ONLY AND CORRECT ANSWERS ARE FOR (i) V(t) = exp (-2e^0.02t+ 2) for 0 < t <10, V(t) = exp(-0.0928 -0.03t- 0.0005t^2) for 10 < t <15, V(t) = exp ( 0.0197 - 0.045t) for 15 <t. AND (ii) C3 £2500 x 0.5877 = £1,469.16 AND (iii) i^2=4.48% pa AND (iv) PV £988.38 The force of interest 8 (t) at any time t, measured in years, is given by: 0<t≤ 10 10t≤15 0.04e0. 0.02t for 8(t) = = 0.03 0.001t for 0.045 for t> 15 (i) Derive, and simplify as far as possible, expressions in terms of t for V(t), where V(t) is the present value of a unit sum of cash flow made at time t. You should derive separate expressions for the three sub-intervals. (ii) Hence, making use of the result in part (i), calculate the value at time t = 3 of a payment of £2,500 made at time t = 15. (iii) Calculate, to the nearest 0.01%, the constant nominal annual rate of interest convertible half-yearly implied by the transaction in part (ii). (iv) Making use of the result in part (i), calculate the present value of a payment stream p(t) paid continuously from time t = 15 to t = 20 at a rate of payment at time t given by: p(t) = 300e 0.02t
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