Plutonium isotopes undergo decay, producing heat. Plutonium isotope 239 (Pu-239) has 1.9 watts per kilogram W of decay kg heat. How much heat, in units of calories (cal, will 3 mole mol of Pu- 239 release after decaying for two hours h? Assume plutonium has a molecular weight of 244 grams per mole
Plutonium isotopes undergo decay, producing heat. Plutonium isotope 239 (Pu-239) has 1.9 watts per kilogram W of decay kg heat. How much heat, in units of calories (cal, will 3 mole mol of Pu- 239 release after decaying for two hours h? Assume plutonium has a molecular weight of 244 grams per mole
Chapter2: The Kinetic Theory Of Gases
Section: Chapter Questions
Problem 77AP: (a) Find the density in SI units of air at a pressure of 1.00 atm and a temperature of 20 , assuming...
Related questions
Question
show all the formulas you used PLEASE it’s really important for me that you show your work and formulas you used to resolve the problem.
Transcribed Image Text:Plutonium isotopes undergo decay, producing heat. Plutonium
isotope 239 (Pu-239) has 1.9 watts per kilogram W
of decay
kg
heat.
How much heat, in units of calories cal, will 3 mole mol of Pu-
239 release after decaying for two hours h?
Assume plutonium has a molecular weight of 244 grams per mole
mol
![Unit Conversion Table
SI Prefixes and Dimensions Table
Angle
1 rad
e rad
SI Prefixes
Example: 1 milligram (mg]- 1 x 10 grams (gd
Power
I hp
57.3
deg
deg
745.7
Example: 1 Megajoule (MJ] - 1x 10 joules (J)
Numbers Greater Than One
180
3.412
BTU / h
Numbers Less Than One
0.00134
hp
cal / min
Prefix
Abbreviation
Prefix
Abbreviation
Area
1 W
Power of 10
Prefix
Power of 10
Prefis
14.34
4,047
m
t Ib /s
-1
deci-
1
deca
-
da
0.7376
1 acre
0.00156
mi
-2
centi-
hecto-
h
1 mi
640
acre
Pressure
3
milli-
3.
kilo-
k
m
1.01325
bar
r
Mega
Energy
1 BTU
33.9
t H0
-6
micro
6.
M
1,055.06
J
1 atm
29.92
in Hg
-9
nano
Giga-
I cal
4.184
J
760
mm Hg
-12
pico-
12
Tera-
т
0.239
cal
101,325
Pa
9.48 10 ITU
0.7376
1J
-15
femto-
15
Peta-
14.7
psi
t Ib
-18
atto-
18
Exa-
E
1 kW h
3,600,000 J
Time
-21
21
Zetta
zepto-
1d
24
h
Force
-24
yocto-
24
Yotta-
1h
60
min
0.225
Ib
1 min
I yr
IN
60
1x 10
dyne
Fundamental Dimensions and Base SI Units
365
I kip
1,000
Ib
Temperature Change
electric current A ampere
N amount
|mol) mole
Length
J light intensity
Jed) candela
T time
Is]
second
1m
3.28
ft
IK
1.8
1 km
1 in
0.621
mi
1.8
"R
L length
(m] meter
O temperature
[K) kelvin
254
cm
12
Volume
M mass
in
(kgl kilogram
5,280
ft
3.785
L
1 mi
1 pal
1.609
km
4
qt
cm or ce
Common Derived, Named Units in the SI System
Base SI Units
1 yd
3
ft
1,000
SI Unit
Derived From
0.264
gal
Dimensions
Dimension
Mass
0.0353
ML
F-ma
(F) newton IN Force (mass (acceleration
1N - 1
I kg
1 Ib
1 shug
1 ton (metric
1 ton (US
2.205
Ib
Force
A oz
cm or ce
33.8
16
oz
I ml.
32.2
Ib
1 m
1,000
L.
ML?
Energy (E) joule
E-Fd
PI Energy (force) (distance)
1J-1N m -1
2,204.62
Ib
16
d oz
pt
I gt
2,000
Ib
2
pt
ML?
(P) watt (W
1w - 1!-1
Power
Named Units
Power - jenergyi / (time)
farad
1 (A s) / V
1 (V s) / A
pascal
poise
1 Pa
IN/ m
1g/ (cm s)
1 em /s
Pressure (P) pascal (Pal Pressure force) / (area)
P-F/A
1 Pa - 1-1
M
henry
1P
LT2
1H
hertz
I Ha
1 St
stoke
IN m
1 V
V IWIA
V-P/I
Voltage - (power) / (current)
ML?
joule
1J
1Nm
volt
Voltage (V) volt
1V -1"-1
T'I
1 (kg m) / s
1v/A
newton
1N
watt
1 W
1J/s
ohm
10
Thinking Like an Engineer 4e
An Aetive Learning Agpproach
Thinking Like an Engineer 4e
An Aetive Learning Approach
an. P
Cte
Geometric Formulas and Physical Constants Table
Equations Table (in order of appearance in textbook
Geometric Formulas
Distance, Velocity and Acceleration
Newton's Second Law
(8.1 Weight
18.2
Rectangular Parallelepiped
Volume - abe
Surface Area 2 (ab+aeb e)
Rectangle
d- vt
F - m a
w = mg
Areaab
v -at
Perimeter - 2 a+ 2b
Density
8.3 Specific Gravity
[8.3] Specific Weight
[8.3]
SG = Pobject
Pwater
w
m
V
Cirele
Sphere
Y=
Arear
Volume -r
Molecular Weight
8.4 Molarity
Temperature: "F to "C
18.5)
Circumference - 2*r
Surface Area4sr
T[*F] – 32 T["C] – 0
Diameter- 2r
MW =
V
180
100
Triangle
Right Cireular Cone
Temperature: "C to K
[8.5 Temperature: "F to "R
[8.5 Pressure
18.6)
Area-bH
Volume -rH
T (K] = T["C] + 273
T ("R] - T ("F] + 460
F
P =
Torus
Right Circular Cylinder
8.6 ideal Gas Law
18.7)
Pascals Law ydrostatic Presure R6 Pressure: Total
Volume -r H
Volume - 2 R
Phydre PgH
Protal - Pydre + Purface
PV-n RT
Lateral Surface Area -2r H
Energy: Work
[8.8 Energy: Potential
[8.8 Energy: Kinetie, translational 8.8
Physical Constants [Value and Units]
W - F Ax
PE - mg AH
KE = m Av?
3x 10
speed of light in a vacuum
Energy: Thermal
[8.8 Power
8.9 Power
8.9)
speed of sound in air (20 "C)
343.59
E
Q-m Cp AT
P = Pout + Post
Euler number (base of natural logarithm) 2.71828..
e
elementary charge of an electron
1.602 x 10 "C
9.65 x 10
Efficiency
[8.10 Current, elated t charge
[8.11) Ohm's Law of Resistance [8.11]
F Faraday's constant
Pout
Pin
Q-It
V-IR
golden ratio
1.61803..
Joule's First Law of Power [8.11 Capacitance, related to charge 8.11] Energy: Capacitor
[8.11)
acceleration due to gravity
9.8 on Earth; 1.6on Earth's Moon
v2
P-VI-=PR
R
Q-CV
E =; Cv?
N
G gravitational constant
6.67 x 10-
k Boltzmann constant
1.38065 x 10
Inductance
8.11 Energy: Inductor
[8.11] Hooke's Law for Spring
[12.3]
dl
NA Avogadro number
6.022 x 10
V =La
E =LF
2
F-k x
ratio of circle circumference to diamcter
3.14159..
Newton's Law of Viscosity [12.3] Kinematic Viscosity
[12.3
Elastic Materials Youngs Modulan (12
R
ideal gas constant
0.08206 - 8314
PaL
Δν
6 = EE
melK
mal K
Ay
11분-1000분-624는
p density of water](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa9b91490-7014-4990-b9a4-62583a5b405c%2Ff7e45974-164a-4dab-b923-5af7b00ccd97%2Fxl0v078_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Unit Conversion Table
SI Prefixes and Dimensions Table
Angle
1 rad
e rad
SI Prefixes
Example: 1 milligram (mg]- 1 x 10 grams (gd
Power
I hp
57.3
deg
deg
745.7
Example: 1 Megajoule (MJ] - 1x 10 joules (J)
Numbers Greater Than One
180
3.412
BTU / h
Numbers Less Than One
0.00134
hp
cal / min
Prefix
Abbreviation
Prefix
Abbreviation
Area
1 W
Power of 10
Prefix
Power of 10
Prefis
14.34
4,047
m
t Ib /s
-1
deci-
1
deca
-
da
0.7376
1 acre
0.00156
mi
-2
centi-
hecto-
h
1 mi
640
acre
Pressure
3
milli-
3.
kilo-
k
m
1.01325
bar
r
Mega
Energy
1 BTU
33.9
t H0
-6
micro
6.
M
1,055.06
J
1 atm
29.92
in Hg
-9
nano
Giga-
I cal
4.184
J
760
mm Hg
-12
pico-
12
Tera-
т
0.239
cal
101,325
Pa
9.48 10 ITU
0.7376
1J
-15
femto-
15
Peta-
14.7
psi
t Ib
-18
atto-
18
Exa-
E
1 kW h
3,600,000 J
Time
-21
21
Zetta
zepto-
1d
24
h
Force
-24
yocto-
24
Yotta-
1h
60
min
0.225
Ib
1 min
I yr
IN
60
1x 10
dyne
Fundamental Dimensions and Base SI Units
365
I kip
1,000
Ib
Temperature Change
electric current A ampere
N amount
|mol) mole
Length
J light intensity
Jed) candela
T time
Is]
second
1m
3.28
ft
IK
1.8
1 km
1 in
0.621
mi
1.8
"R
L length
(m] meter
O temperature
[K) kelvin
254
cm
12
Volume
M mass
in
(kgl kilogram
5,280
ft
3.785
L
1 mi
1 pal
1.609
km
4
qt
cm or ce
Common Derived, Named Units in the SI System
Base SI Units
1 yd
3
ft
1,000
SI Unit
Derived From
0.264
gal
Dimensions
Dimension
Mass
0.0353
ML
F-ma
(F) newton IN Force (mass (acceleration
1N - 1
I kg
1 Ib
1 shug
1 ton (metric
1 ton (US
2.205
Ib
Force
A oz
cm or ce
33.8
16
oz
I ml.
32.2
Ib
1 m
1,000
L.
ML?
Energy (E) joule
E-Fd
PI Energy (force) (distance)
1J-1N m -1
2,204.62
Ib
16
d oz
pt
I gt
2,000
Ib
2
pt
ML?
(P) watt (W
1w - 1!-1
Power
Named Units
Power - jenergyi / (time)
farad
1 (A s) / V
1 (V s) / A
pascal
poise
1 Pa
IN/ m
1g/ (cm s)
1 em /s
Pressure (P) pascal (Pal Pressure force) / (area)
P-F/A
1 Pa - 1-1
M
henry
1P
LT2
1H
hertz
I Ha
1 St
stoke
IN m
1 V
V IWIA
V-P/I
Voltage - (power) / (current)
ML?
joule
1J
1Nm
volt
Voltage (V) volt
1V -1"-1
T'I
1 (kg m) / s
1v/A
newton
1N
watt
1 W
1J/s
ohm
10
Thinking Like an Engineer 4e
An Aetive Learning Agpproach
Thinking Like an Engineer 4e
An Aetive Learning Approach
an. P
Cte
Geometric Formulas and Physical Constants Table
Equations Table (in order of appearance in textbook
Geometric Formulas
Distance, Velocity and Acceleration
Newton's Second Law
(8.1 Weight
18.2
Rectangular Parallelepiped
Volume - abe
Surface Area 2 (ab+aeb e)
Rectangle
d- vt
F - m a
w = mg
Areaab
v -at
Perimeter - 2 a+ 2b
Density
8.3 Specific Gravity
[8.3] Specific Weight
[8.3]
SG = Pobject
Pwater
w
m
V
Cirele
Sphere
Y=
Arear
Volume -r
Molecular Weight
8.4 Molarity
Temperature: "F to "C
18.5)
Circumference - 2*r
Surface Area4sr
T[*F] – 32 T["C] – 0
Diameter- 2r
MW =
V
180
100
Triangle
Right Cireular Cone
Temperature: "C to K
[8.5 Temperature: "F to "R
[8.5 Pressure
18.6)
Area-bH
Volume -rH
T (K] = T["C] + 273
T ("R] - T ("F] + 460
F
P =
Torus
Right Circular Cylinder
8.6 ideal Gas Law
18.7)
Pascals Law ydrostatic Presure R6 Pressure: Total
Volume -r H
Volume - 2 R
Phydre PgH
Protal - Pydre + Purface
PV-n RT
Lateral Surface Area -2r H
Energy: Work
[8.8 Energy: Potential
[8.8 Energy: Kinetie, translational 8.8
Physical Constants [Value and Units]
W - F Ax
PE - mg AH
KE = m Av?
3x 10
speed of light in a vacuum
Energy: Thermal
[8.8 Power
8.9 Power
8.9)
speed of sound in air (20 "C)
343.59
E
Q-m Cp AT
P = Pout + Post
Euler number (base of natural logarithm) 2.71828..
e
elementary charge of an electron
1.602 x 10 "C
9.65 x 10
Efficiency
[8.10 Current, elated t charge
[8.11) Ohm's Law of Resistance [8.11]
F Faraday's constant
Pout
Pin
Q-It
V-IR
golden ratio
1.61803..
Joule's First Law of Power [8.11 Capacitance, related to charge 8.11] Energy: Capacitor
[8.11)
acceleration due to gravity
9.8 on Earth; 1.6on Earth's Moon
v2
P-VI-=PR
R
Q-CV
E =; Cv?
N
G gravitational constant
6.67 x 10-
k Boltzmann constant
1.38065 x 10
Inductance
8.11 Energy: Inductor
[8.11] Hooke's Law for Spring
[12.3]
dl
NA Avogadro number
6.022 x 10
V =La
E =LF
2
F-k x
ratio of circle circumference to diamcter
3.14159..
Newton's Law of Viscosity [12.3] Kinematic Viscosity
[12.3
Elastic Materials Youngs Modulan (12
R
ideal gas constant
0.08206 - 8314
PaL
Δν
6 = EE
melK
mal K
Ay
11분-1000분-624는
p density of water
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you