Pointers Consider the following program: int a - 3; int main(void) int *b = &a; a- 4; int a = 6; int *c = &a; *C= 7; int d = *b + *c; return e; What integer is in variable d just before main returns?
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- In the following program with struct student, which has name and age. There is a pointer to struct student *ptr, but does not assign a value to it. Then, there is a print statement for ptr->age. 1. Why does an error occur when the program is run? #include <stdio.h> //make struct student struct student { charname[25]; int age; }; int main() { //declare pointer to struct student struct student *ptr; //print ptr -> age printf("%d", ptr->age); return0; }Please continue tthe code below --- #include <stdio.h> struct Employee { // declaring the members of the structure char emp_full_name[30]; int pos; float rate_per_hour; int hour_worked; float deduction; float gross_week_pay; float net_week_pay; }; int main() { struct Employee var; // declare the Employee variable struct Employee *ptr; // create a pointer variable (*ptr) ptr = &var ;// assigning the address of var to pointer type variable return 0; }Program in C: Part A: Write the code that defines a struct called dog The following information must be kept in appropriate data types: the name of the dog (char array) the breed of the dog (char array) the wieght of the dog (double) Part B: Write a function called GetDogInfo that declares a temporary dog and fills the 3 data fields with user input (remember to prompt for input) return the filled dog (the function return type is dog) Part C: Write a main function with a function call to GetDogInfo
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- C++ printSmaller is a function that accepts two int parameters and returns no value. It will print the value of the smaller one parameters. The function protoype is as follows: void printSmaller(int num1, int num2); write the statments to read two integers and call this function to display the smaller one.Declare an integer pointer variable intPointer. Initialize it to point to an int variablenamed someInt.Assign the value 451 to someInt and output (cout) the variable someInt and output (cout)the value pointed to by intPointer.Write an assignment statement that indirectly stores 900 into the value pointed to by intPointer.Output (cout) the value pointed to by intPointer and output (cout) the variable someInt,C++ ---- (the bold is code)------ Consider the function interface below: bool isSame(int x, double y); Write a line of code that declares a pointer named Funprt that points to this function.
- C++ Create a class Student that contains three members: roll no, name and mark, and three functions. Write a first inputStudent() function to get data of student class. Write a second getMark() function that returns a student’s mark. Write a third display() function that displays a student’s data. In a main() function, you need to declare 40 students and get data of all students by using inputStudent() function. And also use a pointer array to keep all students by mark greater than 50 and display the searching data of each student in that pointer array (Use the access operator -> to access a pointer points to member functions of the Student class).#include <stdio.h>void cubeByReference( int *nPtr ); // function prototypeint main( void ){ int number = 5; // initialize number printf("The original value of number is %d", number ); // pass address of number to cubeByReference cubeByReference( &number ); printf("\nThe new value of number is %d\n", number );} // end main void cubeByReference( int *nPtr ){ *nPtr = *nPtr* *nPtr* *nPtr;} passing argument by reference - We modify the code above 1- define a second argument (example "int number2 = 9") and a pointer to it 2- define a second function (addByReference) that adds number2 to number - passing both arguments by reference 3- print-out the result (that is in number) Upload the output and .c codeIf integer pointer aPtr is to point at a data item whose value may not change it must be declared as ... A. const int * const aPtr; B. int *aPtr; C. int *const aPtr; D. const int *aPtr;