Pollution begins to enter a lake at time t = 0 at a rate (in gallons per hour) given by the formula f(t), where t is the time (in hours). At the same time, a pollution filter begins to remove the pollution at a rate g(t) as long as the pollution remains in the lake. f(t) = 11 (1 – e -0.5'), g(t) = 0.5t a. How much pollution is in the lake after 12 hours? The amount of pollution that remains in the lake after 12 hours is 74.05 gallons. (Do not round until the final answer. Then round to the nearest hundredth as needed.) b. Use a graphing calculator to find the time after t 0 when the rate that pollution enters the lake equals the rate the pollution is removed. The rate of pollution entering equals the rate of the pollution being removed after (Round to the nearest whole number as needed.) hours.

College Algebra
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ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter6: Exponential And Logarithmic Functions
Section6.1: Exponential Functions
Problem 60SE: The formula for the amount A in an investmentaccount with a nominal interest rate r at any timet is...
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Pollution begins to enter a lake at time t= 0 at a rate (in gallons per hour) given by the formula f(t), where t is the time (in hours). At the same
time, a pollution filter begins to remove the pollution at a rate g(t) as long as the pollution remains in the lake.
f(t) = 11 (1 – e ~0.5'), g(t) = 0.5t
a. How much pollution is in the lake after 12 hours?
The amount of pollution that remains in the lake after 12 hours is 74.05 gallons.
(Do not round until the final answer. Then round to the nearest hundredth as needed.)
b. Use a graphing calculator to find the time after t= 0 when the rate that pollution enters the lake equals the rate the pollution is removed.
The rate of pollution entering equals the rate of the pollution being removed after hours.
(Round to the nearest whole number as needed.)
Transcribed Image Text:Pollution begins to enter a lake at time t= 0 at a rate (in gallons per hour) given by the formula f(t), where t is the time (in hours). At the same time, a pollution filter begins to remove the pollution at a rate g(t) as long as the pollution remains in the lake. f(t) = 11 (1 – e ~0.5'), g(t) = 0.5t a. How much pollution is in the lake after 12 hours? The amount of pollution that remains in the lake after 12 hours is 74.05 gallons. (Do not round until the final answer. Then round to the nearest hundredth as needed.) b. Use a graphing calculator to find the time after t= 0 when the rate that pollution enters the lake equals the rate the pollution is removed. The rate of pollution entering equals the rate of the pollution being removed after hours. (Round to the nearest whole number as needed.)
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