position Now we're going to change things a bit. The charges still have the same sizes and signs (Q₁ = 1.7 μC, Q2 = -3.8 μC, Q3 = 3.3 μC). Q2 is still 0.41 m to the right of Q₁. But now we're free to put Q3 anywhere. Find the location at which Q3 will feel zero net force. Write your answer as the distance Q3 is from Q₁ with a negative sign if Q3 is to the left of Q1, and a plus sign otherwise. Suggestion: Start by deciding qualitatively whether Q3 has to be to the right of Q1 and Q2, to the left of Q1 and Q2, or in between Q1 and Q2. position=-0.00381968 m

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter23: Electric Fields
Section: Chapter Questions
Problem 23.10OQ: Assume the charged objects in Figure OQ23.10 are fixed. Notice that there is no sight line from the...
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How do I solve for te position in this question? 

We have three charges, Q₁, Q2, and Q3, arranged in a straight line. Q₂ is 0.41 m to the right of Q₁. Q3 is 0.2 m to the right of Q2. Check all of
the following statements that are true. If none of them are true, check "None of the above."
1
1
✔A. The force on Q2 because of Q3 will be to the left if those charges are of the same sign.
✔B. The force on Q₁ because of Q2 will be to the right if those charges are of opposite signs.
✔C. The force on Q₁ because of Q3 will be to the right if those charges are of opposite signs.
D. The force on Q3 because of Q1 will be to the left if those charges are of opposite signs.
E. The force on Q3 because of Q2 will be to the right if those charges are of the same sign.
F. None of the above.
force_on_2
Assume that the charges are arranged as before, and that they have the following sizes: Q₁ = 1.7 μC, Q₂: -3.8 μC, Q3 = 3.3 μC.
Calculate the total force on Q2. If the net force is to the left, enter it as a negative number. Otherwise, enter it as a positive number.
force = 2.47563445 N
position
==
=
1.7 μC, Q2
-3.8 μC, Q3 = 3.3 μC). Q2 is
Now we're going to change things a bit. The charges still have the same sizes and signs (₁
still 0.41 m to the right of Q₁. But now we're free to put Q3 anywhere. Find the location at which Q3 will feel zero net force. Write your answer
as the distance Q3 is from Q₁ with a negative sign if Q3 is to the left of Q₁, and a plus sign otherwise.
1.
1
=
Suggestion: Start by deciding qualitatively whether Q3 has to be to the right of Q₁ and Q2, to the left of Q₁ and Q2, or in between Q₁ and Q2.
1
1
1
position = -0.00381968 m
Transcribed Image Text:We have three charges, Q₁, Q2, and Q3, arranged in a straight line. Q₂ is 0.41 m to the right of Q₁. Q3 is 0.2 m to the right of Q2. Check all of the following statements that are true. If none of them are true, check "None of the above." 1 1 ✔A. The force on Q2 because of Q3 will be to the left if those charges are of the same sign. ✔B. The force on Q₁ because of Q2 will be to the right if those charges are of opposite signs. ✔C. The force on Q₁ because of Q3 will be to the right if those charges are of opposite signs. D. The force on Q3 because of Q1 will be to the left if those charges are of opposite signs. E. The force on Q3 because of Q2 will be to the right if those charges are of the same sign. F. None of the above. force_on_2 Assume that the charges are arranged as before, and that they have the following sizes: Q₁ = 1.7 μC, Q₂: -3.8 μC, Q3 = 3.3 μC. Calculate the total force on Q2. If the net force is to the left, enter it as a negative number. Otherwise, enter it as a positive number. force = 2.47563445 N position == = 1.7 μC, Q2 -3.8 μC, Q3 = 3.3 μC). Q2 is Now we're going to change things a bit. The charges still have the same sizes and signs (₁ still 0.41 m to the right of Q₁. But now we're free to put Q3 anywhere. Find the location at which Q3 will feel zero net force. Write your answer as the distance Q3 is from Q₁ with a negative sign if Q3 is to the left of Q₁, and a plus sign otherwise. 1. 1 = Suggestion: Start by deciding qualitatively whether Q3 has to be to the right of Q₁ and Q2, to the left of Q₁ and Q2, or in between Q₁ and Q2. 1 1 1 position = -0.00381968 m
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