Positive charge Q is distributed uniformly around a very thin conducting ring of radius a, as in (Figure 1). You measure the electric field E at points on the ring axis, at a distance from the center of the ring, over a wide range of values of x. Figure Q 0 dQ ds X dE P dE ya 1 of 3 > dE x Your results for smaller values of x are plotted in (Figure 3) as E/x versus x. Why does E/x approach a constan value as a approaches zero. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Ez = Ez Ez Ex Ez = Ez kQ x a = kQ (x²+a²) E = kQx a² = kQx (x²+a²) kQx Ez = a³ Ez kQ I a² E₂ x kQx a kQx (x²+a²)³/2 kQ a³ P Pearson = Reset Help The electric field along the axis a distance from the ring is For

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Chapter6: Gauss's Law
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Problem 86AP: Two non-conducting spheres of radii R1 and R2 are uniformly charged with charge densities p1 and p2...
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Solve both questions in the picture please.

Positive charge is distributed uniformly around a very
thin conducting ring of radius a, as in (Figure 1). You
measure the electric field E at points on the ring axis, at
a distance from the center of the ring, over a wide
range of values of x.
Figure
dQ
ds
r=Vr
X
dE
dEx
a
1 of 3 >
dE
X
Review | Constants
Your results for smaller values of x are plotted in (Figure 3) as E/x versus x. Why does E/x approach a constan
value as x approaches zero.
Drag the terms on the left to the appropriate blanks on the right to complete the sentences.
Ex
Ex
Ex
Ex
=
Ex
X
Ex
Ex
Ex
X
Ex
X
kQx
a²
kQ
(x²+a²)
=
kQ
a
kQx
(x²+²)
kQx
a
kQx
a³
kQ
a²
kQx
3/2
(x²+a²)³/²
kQ
3
P Pearson
Reset
The electric field along the axis a
distance from the ring is
Help
For <a, this gives
and so E/x approach a constant value
of
as x approaches zero.
Transcribed Image Text:Positive charge is distributed uniformly around a very thin conducting ring of radius a, as in (Figure 1). You measure the electric field E at points on the ring axis, at a distance from the center of the ring, over a wide range of values of x. Figure dQ ds r=Vr X dE dEx a 1 of 3 > dE X Review | Constants Your results for smaller values of x are plotted in (Figure 3) as E/x versus x. Why does E/x approach a constan value as x approaches zero. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Ex Ex Ex Ex = Ex X Ex Ex Ex X Ex X kQx a² kQ (x²+a²) = kQ a kQx (x²+²) kQx a kQx a³ kQ a² kQx 3/2 (x²+a²)³/² kQ 3 P Pearson Reset The electric field along the axis a distance from the ring is Help For <a, this gives and so E/x approach a constant value of as x approaches zero.
Positive charge is distributed uniformly around a very
thin conducting ring of radius a, as in (Figure 1). You
measure the electric field E at points on the ring axis, at
a distance from the center of the ring, over a wide
range of values of x.
Figure
a
dQ
ds
r=V
X
dE
dEx
Va
1 of 3
dE
X
Part A
Your results for the larger values of x are plotted in (Figure 2) as Ex² versus x. Why does the quantity Ex²
approach a constant value as x increases.
Drag the terms on the left to the appropriate blanks on the right to complete the sentences.
proportional to x
Submit
point charge
Part C
constant
charged plane
-2
Request Answer
Part B Complete previous part(s)
P Pearson
Review | Constants
Reset Help
Far from the ring, at large values of x, the ring
can be considered as a
constant value as x increases.
So its electric field at large values of x is
hence Ex² approaches a
Transcribed Image Text:Positive charge is distributed uniformly around a very thin conducting ring of radius a, as in (Figure 1). You measure the electric field E at points on the ring axis, at a distance from the center of the ring, over a wide range of values of x. Figure a dQ ds r=V X dE dEx Va 1 of 3 dE X Part A Your results for the larger values of x are plotted in (Figure 2) as Ex² versus x. Why does the quantity Ex² approach a constant value as x increases. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. proportional to x Submit point charge Part C constant charged plane -2 Request Answer Part B Complete previous part(s) P Pearson Review | Constants Reset Help Far from the ring, at large values of x, the ring can be considered as a constant value as x increases. So its electric field at large values of x is hence Ex² approaches a
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