PRACTICE ITUse the worked example above to help you solve this problem. In this example, we show how to find thelocation of a person's center of gravity. Suppose your lab partner has a height L of 171 cm (5 ft, 7 in) anda weight w of 662 N (149 lb). You can determine the position of his center of gravity by having himstretch out on a uniform board supported at one end by a scale, as shown in the figure. If the board'sweight wis 54 N and the scale reading F is 2.85 x 102 N, find the distance of your lab partner's center ofgravity from the left end of the board.cmEXERCISEHINTS: GETTING STARTED T I'M STUCK!Suppose a 447-kg alligator of length 3.8 m is stretched out on a board of the same length weighing 90 N.If the board is supported on the ends as shown in the figure, and the scale reads 1,840 N, find the x-component of the alligator's center of gravity. (Let x = 0 correspond to the left end of the board.)m EXAMPLE 8.5 Locating Your Lab Partner's Center of GravityGOAL Use torque to find a centerof gravity.PROBLEM In this example weshow how to find the location of aperson's center of gravity. Supposeyour lab partner has a height L of173 cm (5 ft, 8 in) and a weight w of715 N (160 lb). You can determinethe position of his center of gravityby having him stretch out on auniform board supported at one endby a scale, as shown in the figure. If the board's weight w, is 49 N and the scale reading F is 3.50 × 10²N, find the distance of your lab partner's center of gravity from the left end of the board.taSOLUTIONApply the second condition ofequilibrium.Substitute expressions for the torques.Solve for xcg and substitute knownvalues.L/2XcgDetermining your lab partner's center of gravity.cgSTRATEGY To find the position x of the center of gravity, compute the torques using an axis throughO. There is no torque due to the normal force n because its moment arm is zero about an axis through O.Set the sum of the torques equal to zero and solve for x,*cg.Στ; = tn + Tw + Twb + TF: = 0Xcg0 - wxcg-w(L/2) + FL = 0FL - W (L/2)W(350 N) (173 cm) - (49 N) (86.5 cm) = 79 cm715 N

Name: PRACTICE ITUse the worked example above to help you solve this proble
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Description: PRACTICE ITUse the worked example above to help you solve this problem. In this example, we show how to find thelocation of a person's center of gravity. Suppose your lab partner has a height L of 171 cm (5 ft, 7 in) anda weight w of 662 N (149 lb).

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PRACTICE IT Use the worked example above to help you solve this problem. In this example, we show how to find the location of a person's center of gravity. Suppose your lab partner has a height L of 171 cm (5 ft, 7 in) and a weight w of 662 N (149 lb). You can determine the position of his center of gravity by having him stretch out on a uniform board supported at one end by a scale, as shown in the figure. If the board's weight w, is 54 N and the scale reading F is 2.85 x 102 N, find the distance of your lab partner's center of gravity from the left end of the board. cm EXERCISE HINTS: GETTING STARTED I'M STUCK! Suppose a 447-kg alligator of length 3.8 m is stretched out on a board of the same length weighing 90 N. If the board is supported on the ends as shown in the figure, and the scale reads 1,840 N, find the x- component of the alligator's center of gravity. (Let x = 0 correspond to the left end of the board.) m

PRACTICE IT Use the worked example above to help you solve this problem. In this example, we show how to find the location of a person's center of gravity. Suppose your lab partner has a height L of 171 cm (5 ft, 7 in) and a weight w of 662 N (149 lb). You can determine the position of his center of gravity by having him stretch out on a uniform board supported at one end by a scale, as shown in the figure. If the board's weight w, is 54 N and the scale reading F is 2.85 x 102 N, find the distance of your lab partner's center of gravity from the left end of the board. cm EXERCISE HINTS: GETTING STARTED I'M STUCK! Suppose a 447-kg alligator of length 3.8 m is stretched out on a board of the same length weighing 90 N. If the board is supported on the ends as shown in the figure, and the scale reads 1,840 N, find the x- component of the alligator's center of gravity. (Let x = 0 correspond to the left end of the board.) m

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter8: Rotational Motion

Section: Chapter Questions

Problem 74A

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