probability of winning. If the metal ball38In the game of roulette, a player can place a $9 bet on the number 32 and have alands on 32, the player gets to keep the $9 paid to play the game and the player is awarded $315. Otherwise, the player isawarded nothing and the casino takes the player's $9. What is the expected value of the game to the player? If you played thegame 1000 times, how much would you expect to lose?The expected value is $(Round to the nearest cent as needed.)The player would expect to lose about $(Round to the nearest cent as needed.)

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Asked Dec 5, 2019
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probability of winning. If the metal ball
38
In the game of roulette, a player can place a $9 bet on the number 32 and have a
lands on 32, the player gets to keep the $9 paid to play the game and the player is awarded $315. Otherwise, the player is
awarded nothing and the casino takes the player's $9. What is the expected value of the game to the player? If you played the
game 1000 times, how much would you expect to lose?
The expected value is $
(Round to the nearest cent as needed.)
The player would expect to lose about $
(Round to the nearest cent as needed.)
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probability of winning. If the metal ball 38 In the game of roulette, a player can place a $9 bet on the number 32 and have a lands on 32, the player gets to keep the $9 paid to play the game and the player is awarded $315. Otherwise, the player is awarded nothing and the casino takes the player's $9. What is the expected value of the game to the player? If you played the game 1000 times, how much would you expect to lose? The expected value is $ (Round to the nearest cent as needed.) The player would expect to lose about $ (Round to the nearest cent as needed.)

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Expert Answer

Step 1

It is given that probability of winning the game is 1/38. Therefore, probability of losing the game is 37/38.

Step 2

The expected value of the gam...

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Expected value = expected gain + expected loss 대끓이 37 (315)+ (9) 38 38 -18 38 = $ – 0.474

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