Problem 1: Arock of mass m = 0.56 kg is attached to a massless string of length L = 0.68 m. The rock is swung in a vertical circle faster and faster up to a speed of v = 2.8 m/s, at which time the string breaks. This occurs when the string is horizontal as shown in the figure. Break Part (a) What is the magnitude of the tension, in newtons, at which the string breaks? Numeric : A numeric value is expected and not an expression. Tf = Part (b) How high, in meters, does the rock travel? Use a value of h = 0 at the location of the break. Numeric : A numeric value is expected and not an expression. h =

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter5: More Applications Of Newton’s Laws
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Work and Kinetic Energy Q1: Please answer each part step by step and explain each step (even if minor)  in detail please.

Problem 1: A rock of mass m = 0.56 kg is attached to a massless string of length L =
0.68 m. The rock is swung in a vertical circle faster and faster up to a speed of v = 2.8
m/s, at which time the string breaks. This occurs when the string is horizontal as shown
in the figure.
Break
Part (a) What is the magnitude of the tension, in newtons, at which the string breaks?
Numeric : A numeric value is expected and not an expression.
Tf =
Part (b) How high, in meters, does the rock travel? Use a value of h = 0 at the location of the break.
Numeric : A numeric value is expected and not an expression.
h =
Transcribed Image Text:Problem 1: A rock of mass m = 0.56 kg is attached to a massless string of length L = 0.68 m. The rock is swung in a vertical circle faster and faster up to a speed of v = 2.8 m/s, at which time the string breaks. This occurs when the string is horizontal as shown in the figure. Break Part (a) What is the magnitude of the tension, in newtons, at which the string breaks? Numeric : A numeric value is expected and not an expression. Tf = Part (b) How high, in meters, does the rock travel? Use a value of h = 0 at the location of the break. Numeric : A numeric value is expected and not an expression. h =
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