Problem 1 Convert the following relation to 2NF, and then to 3NF. Show both conversions. (h, n, c, a, f, k, p, r, g, i, m, b, o, d, j, I, s, e) Functional Dependencies: m, b >I n >o p>o a >r h >g c>i h >d
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Q: Convert the following relation to 2NF, and then to 3NF. Show both conversions. (h, n, c, a, f, k, p,…
A: Solution :: functional dependencies: p-->j,m; b-->l; h-->g; n-->p; n-->o;…
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- Suppose we have a relational database with five tables.table key AttributesS(sid, A) SidT(tid, B) TidU(uid, C) UidR(sid, tid, D) sid, tidQ(tid, uid, E) tid, uidHere R implements a many-to-many relationship between the entities implemented with tables S and T, and Q implements a many-to-many relationship between the entities implemented with tables T and U.D. Suppose you replaced SELECT with SELECT DISTINCT in your queries from parts (a) and Could one of these modified queries return more records than the other? If so, which one? Justify your answer. E. Consider again your query from part (a). If pair sid, uid is returned by this query then there must exist at least one “path” that goes from from table S to table T (via relation R) and then from table T to table U (via relation Q). Note that there can be many such paths for a given pair sid, uid. Write an SQL query that returns records of the form tid, total where…Design a relational database schema from the Car Sharing IS domain class diagram. Output should look like image number 2Convert the following relation to 2NF, and then to 3NF. Show both conversions. (h, n, c, a, f, k, p, r, g, i, m, b, o, d, j, l, s, e) Functional Dependencies: p → j m, b → l h → g n → p n → o c → i n → j p → o h → d s → e a → r
- To illustrate, imagine you have a database containing the x, y locations and names of several eateries. We shall pretend that just the following kinds of inquiries are made: Whether or if a restaurant can be located at a certain address is the focus of the inquiry. Which indexing system is preferable: B-tree or R-tree? Why?No written by hand solution Consider a database schema ABCDEFG with the functional dependencies → G→F, → FE→D, → C→AB. List all keys for the scheme. I need a thorough explanation.Consider, for instance, the database management system that is used by an airline; such a system often has snapshot isolation as one of its many capabilities. I was hoping that you could provide me an example of a non-serializable execution that the airline is ready to endure in order to get better performance as a whole. If you could, that would be much appreciated.
- 4. (a) Why is normalization important in database design? Consider the universal relation R = {A, B, C, D, E, F, G, H, I, J} and the set of functional dependencies F = { AB → C, A → DE, B → F, F → GH, D → IJ }.What is the key for R? Decompose R into 2NF (Second Normal Form) and then 3NF (Third Normal Form) relations. (b) Consider a relation schema R = (X, Y, Z) on which the following functional dependencies hold: { XY → Z, Z → X }. Show that the schema R is not in BCNF (Boyce-Codd Normal Form) but it is in 3NF (Third Normal Form).Suppose we have a relational database with five tables. table key Attributes S(sid, A) Sid T(tid, B) Tid U(uid, C) Uid R(sid, tid, D) sid, tid Q(tid, uid, E) tid, uid Here R implements a many-to-many relationship between the entities implemented with tables S and T, and Q implements a many-to-many relationship between the entities implemented with tables T and U. A. Write an SQL query that returns all records of the form sid, uid where sid is the key of an S- record and uid is the key of a U-record and these two records are related through the relations R and Q. Use SELECT and not SELECT DISTINCT in your query. B. Write an SQL query that returns records of the form A, C where the A-value is from an S- record and the C-value is from a U-record and these two records are related through the relations R and Q. Use SELECT and not SELECT DISTINCT in your query. C. Could one of your queries from parts (a) and (b) return more records than the other? If so, which one? Justify your answer. D.…Suppose we have a relational database with five tables. table key Attributes S(sid, A) Sid T(tid, B) Tid U(uid, C) Uid R(sid, tid, D) sid, tid Q(tid, uid, E) tid, uid Here R implements a many-to-many relationship between the entities implemented with tables S and T, and Q implements a many-to-many relationship between the entities implemented with tables T and U. A. Write an SQL query that returns all records of the form sid, uid where sid is the key of an Srecord and uid is the key of a U-record and these two records are related through the relations R and Q. Use SELECT and not SELECT DISTINCT in your query. B. Write an SQL query that returns records of the form A, C where the A-value is from an Srecord and the C-value is from a U-record and these two records are related through the relations R and Q. Use SELECT and not SELECT DISTINCT in your query. C. Could one of your queries from parts (a) and (b) return…
- Using the Crow’s Foot Diagrram technique, draw a database design for the attached database.A database of application of wholesaler can be modelled by means of the relations price, in_stock and supplies. Price is a relation over products1…30, which models the association between prices and stock items. In_stock is a relation over productsN, which models the association between stock items and the current number in stock of product. Supplies is a relation over suppliersproducts which models the relation between a supplier and the product that is delivered by that supplier. If the current value of these relations are following:price = {(nut, 5), (bolt, 13), (screw, 3), (board, 25), (fastener, 23)}, in_stock = {(nut, 700), (bolt, 2200), (screw, 55), (board, 0), (fastener, 600)}, supplies = {(Thomas, nut), (Thomas, bolt), (Wilks, bolt), (Wilks, screw), (Wilks, board), (Wilks, fastener), (Rogers, board), (Rogers, fastener)}, then what is the value of the following expressions? i. {nut, bolt} priceii. dom(price 1…15).iii. rng(price 1…10).iv. dom(supplies; (in_stock {0})). v.…Discuss the CAP theorem and its implications for designing database architectures. Provide real-world examples to illustrate its principles.