PROBLEM 1:The continuous floor beam ABCD is shown in the figure. It has a 100 mm slab thickness and the beamsbxh is 300 mm x 500 mm. Column section is 0.30 m x 0.30 m.Live load = 3.6 KPaSuperimposed Dead load = 2.6 KPaConcrete weighs = 24 KN/m3L = 8 m.S = 2.8 m.2.82.8Siahs.neglet the live load ReduchonO Compute the positive moment for beam EF.2.8M8 m8 m8 mCompute the negative moment at the face of support ECompute the negative moment at F

Given, Slab thickness=100 mm Live load=3.6 kPa L=8 m S=2.8 m Superimposed load =2.6 kPa Concrete…

PROBLEM 1: The continuous floor beam ABCD is shown in the figure. It has a 100 mm slab thickness and the beams bxhis 300 mm x 500 mm. Column section is 0.30 m x 0.30 m. Live load = 3.6 KPa Superimposed Dead load = 2.6 KPa Concrete weighs = 24 KN/m L= 8 m. S= 2.8 m. 28 neglect the live load Reduchion O Compute the positive moment for beam EF. 2.8 8 m 8 m 8m O Compute the negative moment at the face of support E OCompute the negative moment at F

PROBLEM 1: The continuous floor beam ABCD is shown in the figure. It has a 100 mm slab thickness and the beams bxhis 300 mm x 500 mm. Column section is 0.30 m x 0.30 m. Live load = 3.6 KPa Superimposed Dead load = 2.6 KPa Concrete weighs = 24 KN/m L= 8 m. S= 2.8 m. 28 neglect the live load Reduchion O Compute the positive moment for beam EF. 2.8 8 m 8 m 8m O Compute the negative moment at the face of support E OCompute the negative moment at F

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter7: Settlement Of Shallow Foundations

Section: Chapter Questions

Problem 7.2P: A planned flexible load area (see Figure P7.2) is to be 3 m × 4.6 m and carries a uniformly...

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