PROBLEM 1: The homogeneous structure shown weighs 21.45 kN per square meter of cross-section. The structure is subject to horizontal uniformly distributed load P1 and triangularly distributed load P2 perpendicular to side AB. Given: H1 = 9 m; H2 = 6 m; H3 = 12 m X1 = 6 m; X2 = 5 m P1 = 220 kN/m; P2 = 280 kN/m Required Answer Equivalent force of uniform load P1 1980.00 Total weight of the structure, W 3603.60 Horizontal component of the resultant, Rx 300.00

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Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.