Problem 10: On a one lane road, a person driving a car at v = 78 mi/h suddenly notices a truck 0.65 mi in front of him. That truck is moving in the same direction at v2 = 41 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v2 during time interval At. The smallest magnitude of acceleration required for the car to avoid a collision is a. During this problem, assume the direction of motion of the car is the positive direction. Refer to the figure.

College Physics
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Chapter2: Kinematics
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Part (a) Enter an expression, in terms of defined quantities, for the distance, Ax,, traveled by the truck during the time interval At.
Part (b) Enter an expression for the distance, Ax¡, traveled by the car in terms of v1, v2 and a.
Part (c) Enter an expression for the acceleration of the car, a, in terms of v1, v2, and At.
Part (d) Enter an expression for Ax¡ in terms of Ax, and d when the driver just barely avoids collision.
Part (e) Enter an expression for Ax¡ in terms of vị, v2, and At.
Part (f) Enter an expression for At in terms of d, v1, and v2.
Part (g) Calculate the value of At in hours.
Part (h) Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms of d, v1, and v2.
Part (i) Calculate the value of a in meters per second squared.
Transcribed Image Text:Part (a) Enter an expression, in terms of defined quantities, for the distance, Ax,, traveled by the truck during the time interval At. Part (b) Enter an expression for the distance, Ax¡, traveled by the car in terms of v1, v2 and a. Part (c) Enter an expression for the acceleration of the car, a, in terms of v1, v2, and At. Part (d) Enter an expression for Ax¡ in terms of Ax, and d when the driver just barely avoids collision. Part (e) Enter an expression for Ax¡ in terms of vị, v2, and At. Part (f) Enter an expression for At in terms of d, v1, and v2. Part (g) Calculate the value of At in hours. Part (h) Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms of d, v1, and v2. Part (i) Calculate the value of a in meters per second squared.
Problem 10: On a one lane road, a person driving a car at v = 78 mi/h suddenly notices a
truck 0.65 mi in front of him. That truck is moving in the same direction at v2 = 41 mi/h. In order to
avoid a collision, the person has to reduce the speed of his car to vz during time interval At. The
smallest magnitude of acceleration required for the car to avoid a collision is a. During this problem,
assume the direction of motion of the car is the positive direction. Refer to the figure.
d.
Transcribed Image Text:Problem 10: On a one lane road, a person driving a car at v = 78 mi/h suddenly notices a truck 0.65 mi in front of him. That truck is moving in the same direction at v2 = 41 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to vz during time interval At. The smallest magnitude of acceleration required for the car to avoid a collision is a. During this problem, assume the direction of motion of the car is the positive direction. Refer to the figure. d.
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