PROBLEM 11.124 Knowing that at the instant shown block A has a velocity of 8 in./s and an acceleration of 6 in./s both directed down the incline, determine (a) the velocity of block B. (b) the acceleration of block B. B メ。= Sinls yさ25 15° %3D Xp = 6 in /s? y > 25 Xg = ? Xg = ? 25° 40 L= XA + XA (xg-Xx) 16 %3D 25 = xA + XA + - 2 - 2(8) = -16 in/s O = 40 2* A 16 cos 40° 8 cos 25° B/A %3D ×6- ×。マ Xe= X8%% + xA ion) ( Now just ned direct %3D A - -16 cos 40° + 8 cos 25° = - 12.258 + 7.250

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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PROBLEM 11.124
Knowing that at the instant shown block A has a velocity of
8 in./s and an acceleration of 6 in./s both directed down the
incline, determine (a) the velocity of block B. (b) the
acceleration of block B.
B
X。= Sinls yさ25
6 in /52 y> 25
Xg = ? X = ?
15°
%3D
25°
A
40
(xB-Xx)
XA + XA +
= xA + XA +
- 2x A
-2(8) = -16 in/s
*B - *A 7 xe =
16
%3D
8
25
O =
40
8 cos 25°
B/A
16 cos 40°
Xea + ia (Now just naed dire chon)
%3D
|
- -16 cos 4O° + 8 cos 25°
= - 12.258 + 7.25o
Transcribed Image Text:PROBLEM 11.124 Knowing that at the instant shown block A has a velocity of 8 in./s and an acceleration of 6 in./s both directed down the incline, determine (a) the velocity of block B. (b) the acceleration of block B. B X。= Sinls yさ25 6 in /52 y> 25 Xg = ? X = ? 15° %3D 25° A 40 (xB-Xx) XA + XA + = xA + XA + - 2x A -2(8) = -16 in/s *B - *A 7 xe = 16 %3D 8 25 O = 40 8 cos 25° B/A 16 cos 40° Xea + ia (Now just naed dire chon) %3D | - -16 cos 4O° + 8 cos 25° = - 12.258 + 7.25o
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