= Problem 19.02. A molecule with mass m = 9.11 × 10-25 kg and net charge de 1.602 × 10-19 C is accelerated from rest across a potential difference of V 200 V. (a) What is the molecule's change in potential energy SU? (b) What is the molecule's final velocity vf? =

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Chapter19: Electric Potential And Electric Field
Section: Chapter Questions
Problem 30PE: In nuclear fission. a nucleus splits roughly in half. (a) What is the potential 2.00 10-14 m from a...
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= 1.602 ×
19
=
Problem 19.02. A molecule with mass m = 9.11 × 10-25 kg and net charge de
10-1⁹ C is accelerated from rest across a potential difference of V = 200 V. (a) What is the
molecule's change in potential energy ¡U? (b) What is the molecule's final velocity vf?
Transcribed Image Text:= 1.602 × 19 = Problem 19.02. A molecule with mass m = 9.11 × 10-25 kg and net charge de 10-1⁹ C is accelerated from rest across a potential difference of V = 200 V. (a) What is the molecule's change in potential energy ¡U? (b) What is the molecule's final velocity vf?
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